Pass list items as arguments to method

Question

Assuming i have a method definition like this do_stuff(*arg).

I have a list of values, ['a','b',...]. How best can i pass the values of this list as individual arguments to the do_stuff method as do_stuff('a','b',...) ?

I've unsuccessfully tried using list comprehension - do_stuff([str(value) for value in some_list])

I am hoping i don't have to change do_stuff() to accept a list

Any pointers would be appreciated.

Use `*`,... A list comprehension just creates a list, you *already have a list* — juanpa.arrivillaga, Dec 27 '21 at 20:12

score 1 · Answer 1 · answered Dec 27 '21 at 20:13

1

It's the same syntax, with the *:

do_stuff(*['a','b','c'])

answered Dec 27 '21 at 20:13

Tim Roberts

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Thank you!. Knew it was something obvious – dev Dec 27 '21 at 20:55

score 1 · Accepted Answer · answered Dec 27 '21 at 20:14

1

You can pass them using the "*" operator. So an example would be like this:

def multiplyfouritems(a,b,c,d):
    return a*b*c*d

multiplyfouritems(*[1,2,3,4])

answered Dec 27 '21 at 20:14

Yusuf Tamer

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Strictly speaking, it's not an operator. It's part of the function-call syntax. – chepner Dec 27 '21 at 20:17
And it's called "splat" :) – Mad Physicist Dec 27 '21 at 20:18

Pass list items as arguments to method

2 Answers2