I recommend using dplyr for this which is a very common package.
library(dplyr)
mtcars[which(mtcars$mpg>30),] %>% arrange(desc(mpg), descending = FALSE)
               mpg cyl disp  hp drat    wt  qsec vs am gear carb
Toyota Corolla 33.9   4 71.1  65 4.22 1.835 19.90  1  1    4    1
Fiat 128       32.4   4 78.7  66 4.08 2.200 19.47  1  1    4    1
Honda Civic    30.4   4 75.7  52 4.93 1.615 18.52  1  1    4    2
Lotus Europa   30.4   4 95.1 113 3.77 1.513 16.90  1  1    5    2
In fact, dplyr has a pipe operator which makes the filtering easier too.
mtcars %>% 
  filter(mpg > 30)%>% 
  arrange(desc(mpg), descending = FALSE)
               
                mpg cyl disp  hp drat    wt  qsec vs am gear carb
Toyota Corolla 33.9   4 71.1  65 4.22 1.835 19.90  1  1    4    1
Fiat 128       32.4   4 78.7  66 4.08 2.200 19.47  1  1    4    1
Honda Civic    30.4   4 75.7  52 4.93 1.615 18.52  1  1    4    2
Lotus Europa   30.4   4 95.1 113 3.77 1.513 16.90  1  1    5    2
If you must use base R, it's (in my opinion) not as syntactically pretty but just as valid:
x <- mtcars[which(mtcars$mpg>30),] #this makes a new dataframe which is easier to work with
x[order(x$mpg, decreasing = TRUE),]
                mpg cyl disp  hp drat    wt  qsec vs am gear carb
Toyota Corolla 33.9   4 71.1  65 4.22 1.835 19.90  1  1    4    1
Fiat 128       32.4   4 78.7  66 4.08 2.200 19.47  1  1    4    1
Honda Civic    30.4   4 75.7  52 4.93 1.615 18.52  1  1    4    2
Lotus Europa   30.4   4 95.1 113 3.77 1.513 16.90  1  1    5    2
Finally, if you insist on one line, you can even do that.
mtcars[which(mtcars$mpg>30),][order(mtcars[which(mtcars$mpg>30),"mpg"], decreasing = TRUE),]
                mpg cyl disp  hp drat    wt  qsec vs am gear carb
Toyota Corolla 33.9   4 71.1  65 4.22 1.835 19.90  1  1    4    1
Fiat 128       32.4   4 78.7  66 4.08 2.200 19.47  1  1    4    1
Honda Civic    30.4   4 75.7  52 4.93 1.615 18.52  1  1    4    2
Lotus Europa   30.4   4 95.1 113 3.77 1.513 16.90  1  1    5    2