If you're looking for a complete Python Selenium solution for solving the Wordle Game programmatically, here's one that uses the SeleniumBase framework. The solution comes with a YouTube video: Solving Wordle using SeleniumBase, as well as the Python code of the solution, and a GIF of what to expect:
The code uses special SeleniumBase ::shadow selectors in order to pierce through multiple layers of Shadow-DOM. Here's the code below, which can be run after calling pip install seleniumbase to get all the Python dependencies:
import ast
import random
import requests
from seleniumbase import __version__
from seleniumbase import BaseCase
class WordleTests(BaseCase):
word_list = []
def initalize_word_list(self):
js_file = "https://www.powerlanguage.co.uk/wordle/main.e65ce0a5.js"
req_text = requests.get(js_file).text
start = req_text.find("var La=") + len("var La=")
end = req_text.find("],", start) + 1
word_string = req_text[start:end]
self.word_list = ast.literal_eval(word_string)
def modify_word_list(self, word, letter_status):
new_word_list = []
correct_letters = []
present_letters = []
for i in range(len(word)):
if letter_status[i] == "correct":
correct_letters.append(word[i])
for w in self.word_list:
if w[i] == word[i]:
new_word_list.append(w)
self.word_list = new_word_list
new_word_list = []
for i in range(len(word)):
if letter_status[i] == "present":
present_letters.append(word[i])
for w in self.word_list:
if word[i] in w and word[i] != w[i]:
new_word_list.append(w)
self.word_list = new_word_list
new_word_list = []
for i in range(len(word)):
if (
letter_status[i] == "absent"
and word[i] not in correct_letters
and word[i] not in present_letters
):
for w in self.word_list:
if word[i] not in w:
new_word_list.append(w)
self.word_list = new_word_list
new_word_list = []
def test_wordle(self):
self.open("https://www.powerlanguage.co.uk/wordle/")
self.click("game-app::shadow game-modal::shadow game-icon")
self.initalize_word_list()
keyboard_base = "game-app::shadow game-keyboard::shadow "
word = random.choice(self.word_list)
total_attempts = 0
success = False
for attempt in range(6):
total_attempts += 1
word = random.choice(self.word_list)
letters = []
for letter in word:
letters.append(letter)
button = 'button[data-key="%s"]' % letter
self.click(keyboard_base + button)
button = 'button[data-key="↵"]'
self.click(keyboard_base + button)
self.sleep(1) # Time for the animation
row = 'game-app::shadow game-row[letters="%s"]::shadow ' % word
tile = row + "game-tile:nth-of-type(%s)"
letter_status = []
for i in range(1, 6):
letter_eval = self.get_attribute(tile % str(i), "evaluation")
letter_status.append(letter_eval)
if letter_status.count("correct") == 5:
success = True
break
self.word_list.remove(word)
self.modify_word_list(word, letter_status)
self.save_screenshot_to_logs()
print('\nWord: "%s"\nAttempts: %s' % (word.upper(), total_attempts))
if not success:
self.fail("Unable to solve for the correct word in 6 attempts!")
self.sleep(3)
This solution requires minimum SeleniumBase version 2.4.0 (or newer) due to updated Shadow-DOM methods. (Here are the Release Notes of that version.)
Note that SeleniumBase tests are run using pytest. Also, the Wordle website appears slightly differently when opened using headless Chrome, so don't use Chrome's headless mode when running this example.
