Argument definitions in printf()

Question

In the following C code:

printf( "Coffee!" );

and

 scanf("%d", &coffee); 

 printf("\nI’m baking %d coffee!", coffee); 

Are "Coffee!" and coffee considered arguments?

Answer 1

You have provided one argument to the first call to printf(), and you have provided two arguments to the call to scanf() and two more to the second call to printf().

The C standard defines both 'argument' and 'parameter':

• §3.3 argument
  actual argument
  actual parameter (deprecated)
  expression in the comma-separated list bounded by the parentheses in a function call expression, or a sequence of preprocessing tokens in the comma-separated list bounded by the parentheses in a function-like macro invocation.
• §3.16 parameter
  formal parameter
  formal argument (deprecated)
  object declared as part of a function declaration or definition that acquires a value on entry to the function, or an identifier from the comma-separated list bounded by the parentheses immediately following the macro name in a function-like macro definition.

Answer 2

"Are "Coffee!" and coffee considered Arguments?"

EDITED (in response to corrected original post by Jonathan L.)

Yes, they are both arguments.

• In the first printf(), "Coffee!" is a single string literal argument.
• In the second printf() : coffee is the 2nd argument, an int value.
• And finally it plays a role as the 2nd argument in the scanf() statement as the location to be changed, or in short the address of coffee (&coffee)

Of course this all assumes that coffee was defined similar to;

int coffee = 0; 

Note on arguments and parameters... (mentioned in comments under question)
When a function is called, the values that are passed during the call are referred to as arguments. The values which are used to define the type of argument used in a function prototype are referred to as parameters. (reference)