variable in c++ is changing in a function

Question

I have a simple converting function however the variable is changing.

void convert_print(std::string type,int num)
{
   if(type=="oct"){
       std::cout << num << " oct value is: " << std::oct << num << endl;
   }
   else if(type == "hex"){
      std::cout << num << " hex value is: " << std::hex << num << endl;
   }
}

int main()
{
   int num = 30;
   convert_print("hex",num);
   convert_print("oct",num);
}

Prints

30 hex value is: 1e 
1e value is: 30

Why is num getting changed to 1e when I call the function again. I never reassigned num

score 4 · Accepted Answer · answered Jan 29 '22 at 01:11

4

You haven't told cout to reset the formatting after your last call. This question describes how to restore it. Restore the state of std::cout after manipulating it

answered Jan 29 '22 at 01:11

Daniel A. White

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[`std::hex` is "Sticky"](https://stackoverflow.com/questions/1532640/which-iomanip-manipulators-are-sticky) – user4581301 Jan 29 '22 at 01:13
Thank you I am getting back into c++. – user3525290 Jan 29 '22 at 20:24

variable in c++ is changing in a function

1 Answers1