regular expression in python to extract words that contain @ but not dot

Question

I am using Python to extract words from a text. I want to extract word that contain@ but not dot.

Regular expression should match following: @bob, cat@bob
Regular expression should not match: xyz@bob.com.

I tried following: (?:\w+)?@\w+(?!\.) - but it extracts @bob, cat@bob and xyz@bo.

Just to elaborate, if I have text "hi @bob and cat@bob my email is xyz@bob.com" I want to extract @bob and cat@bob only from this text. My regular expression above extracts part of xyz@bob.com (precisely it extracts xyz@bo). How can I avoid extracting xyz@bob.com completely.

your test cases are not clear. please give 3 typical input and expected output. — Lei Yang, Feb 10 '22 at 05:40
Your regex works for me as expected(so, doesn't find pattern in the last string).....Are you sure you saved your code before running finally ^^ — Tulika, Feb 10 '22 at 05:49

score 0 · Answer 1 · answered Feb 10 '22 at 06:20

0

I was finally able to find a solution. The following expression worked for me: (?:\w+)?@\w+\b(?!.)

answered Feb 10 '22 at 06:20

Harpreet Singh

11
2

this works too: `[a-zA-Z0-9_+-]*@[a-zA-Z0-9_+-]*\s` – Ali Feb 10 '22 at 06:27
1

`\w*@\w+\b(?!\.)` will do. No need to require one or more chars (with `\w+`) and then make them all optional (with an optional non-capturing group, `(?:...)?`). `(?:a+)?` = `a*`. – Wiktor Stribiżew Feb 10 '22 at 08:54
@WiktorStribiżew. That about leading dot? – Mad Physicist Feb 10 '22 at 08:55
Thanks @WiktorStribiżew. I further modified the expression so that it matches xyz@bob. (i.e. when this comes at the end of sentence) but not xyz@bob.com -- `\w*@\w+\b(?!\.\w+)` – Harpreet Singh Feb 10 '22 at 16:05

regular expression in python to extract words that contain @ but not dot

1 Answers1