I want to display inputs of for loop

Question

I have created a user input.

I want to display the inputs I have taken from the for loop.

i dont know how to arrays tho (edited) This is all I have. My code explains more:

Item Priority Financed Cost
---- -------- -------- -----------
 1      1        n       39030.15
 2      3        y     1200000.00
 3      2        n      350500.25
---- -------- -------- -----------
                     $ 1589530.40

something like this

here is my code

#define _CRT_SECURE_NO_WARNINGS

#define minINCOME 500.00
#define maxINCOME 400000.00

#include <stdio.h>

int main(void)
{
    float userIncome ;
    int wishlistItems;
    float itemCost;
    const float minitemCost = 100.00;
    int itemImp;
    char finance;
    
    printf("+--------------------------+\n"
           "+   Wish List Forecaster   |\n"
           "+--------------------------+\n\n");
   
    do
    {
        printf("Enter your monthly NET income: $");
        scanf(" %f", &userIncome);

        if (userIncome < minINCOME)
        {
            printf("ERROR: You must have a consistent monthly income of at least $500.00\n\n");
        }

        else if (userIncome > maxINCOME)
        {
            printf("ERROR: Liar! I'll believe you if you enter a value no more than $400000.00\n\n");
        }
    } while( (userIncome > maxINCOME || userIncome < minINCOME));

    do
    {
        printf("How many wish list items do you want to forecast?: ");
        scanf(" %d", &wishlistItems);
        if (wishlistItems > 10 || wishlistItems < 1)
        {
            printf("ERROR: List is restricted to between 1 and 10 items.\n\n");
        }
    } while (wishlistItems > 10 || wishlistItems < 1);

    for (size_t i = 1; i <= wishlistItems; i++ )
    {
        do {

            printf("Item-%d Details:\n", i);
            printf("   Item cost: $");
            scanf(" %f", &itemCost);

            if (itemCost < minitemCost)
            {
                printf("      ERROR: Cost must be at least $100.00\n");
            }
        } while (itemCost < minitemCost);

        do {
            printf("   How important is it to you? [1=must have, 2=important, 3=want]: ");
            scanf(" %d", &itemImp);

            if (itemImp  < 1 || itemImp >3 )
            {
                printf("      ERROR: Value must be between 1 and 3\n");
            }
        } while (itemImp < 1 || itemImp >3);
    
        do {
            printf("   Does this item have financing options? [y/n]: ");
            scanf(" %c", &finance);
            if (finance != 'y' || finance != 'n')
            {
                printf("      ERROR: Must be a lowercase 'y' or 'n'\n");
            }
        } while (finance != 'y' || finance != 'n');
    }

    return 0;
} 

Answer 1

Given that wishlistItems is limited to 10, there shouldn't be any issue using an array. Even if the user doesn't fill it up fully, 10 items is not that much memory to be concerned about.

On the other hand, given that theoretically you want to build a scalable program, and wishlistItems can change, I would consider a linked list here. It will require pointers and dynamic memory allocation (as pointed by Steve), but allows you to maintain all the data in memory, while allocating the exact memory size required here.

Each item on the list will look approximately like this:

    struct wish_list_item {
    float cost;
    int impact;
    char finance;
    struct wish_list_item *next;
};

Where next points to the next item on the list, or is NULL if it is the last item. Then I would suggest to implement a couple of helper functions to work with the list more comfortably (add_element, del_element, print_list, find_element, insert_element), all according to your needs. Should be easy to find example implementations, given that Linked list is the second most-used data structure after array.