sorting 2nd list in the same way 1nd list sorted

Question

Suppose I got to list X, Y of integers both size N. the vector Y, corresponding to the X , (the xi label is yi)

Now I want to sort X and then sort Y in same order if I done it in java I would override the sort method, but i am kind of new in python... any nice method to do so?

We need sample input and output data in order to be able to understand your problem. You also seem to have forgotten to post the code that's troubling you — DarkKnight, Feb 24 '22 at 17:28
You can override the sort function with the key argument. Have a look at: https://stackoverflow.com/questions/2531952/how-to-use-a-custom-comparison-function-in-python-3 — Kavli, Feb 24 '22 at 17:28

score 0 · Answer 1 · answered Feb 24 '22 at 17:26

0

Not sure if this is what you mean by "nice":

combo = sorted(zip(x,y))

sorted_x = [a for a,b in combo]
sorted_y = [b for a,b in combo]

answered Feb 24 '22 at 17:26

Scott Hunter

48,888
12
60
101

score 0 · Accepted Answer · answered Feb 24 '22 at 17:27

Use zip() to bind each data point in X with its associated data point in Y. Then use sorted() and a list comprehension to read off the result:

x = [3, 1, 2]
y = [5, 4, 6]

# Prints [4, 6, 5]
# These values are sorted in ascending order of corresponding x-value:
# 1 --> 4
# 2 --> 6
# 3 --> 5
result = [y_data for _, y_data in sorted(zip(x, y))]

print(result)

sorting 2nd list in the same way 1nd list sorted

2 Answers2