No output after calling function (Python)

Question

just a total newbie here. I am learning Python and was trying to call the function as below, yet I cannot see any output.

nums = [0,1,2,7,14]
def has_lucky_num(nums):
    #return numbers that can be divisible by 7
    for num in nums:
        if num % 7 == 0:
            return True
        return False
has_lucky_num(nums)

Can someone tell me why it did not work? Thanks in advance.

Answer 1

Your program isn't printing anything because it doesn't have a print() command anywhere. Try the following line : print(has_lucky_nums(nums)), and it should print your True or False result! So you would have the following code :

nums = [0,1,2,7,14]
def has_lucky_num(nums):
    #return numbers that can be divisible by 7
    for num in nums:
        if num % 7 == 0:
            return True
        return False
print(has_lucky_num(nums))

Answer 2

Your function has a problem:

• You must put the return False after loop because if you don't it return immediately after checking first item So function code must be this:

nums = [0,1,2,7,14]
def has_lucky_num(nums):
    #return numbers that can be divisible by 7
    for num in nums:
        if num % 7 == 0:
            return True
    return False

If you want to see result you must print the result returns by the function has_lucky_num()

So all you have to do is to add a print like this:

Instead Of:

has_lucky_num(nums)

Replace With:

print(has_lucky_num(nums))

Output:

True

Answer 3

Return True and Return False won't actually display anything. You need to do something with those values, for instance:

if has_lucky_num(nums) == True:
    print(f'{nums} has a lucky number!')
else:
    print(f'{nums} has a lucky number!')
```