how to compare every element in array to a value

Question

What I essantily want to do is compare all values in array to 123 in an if statment

let values = [1, 2, 3, 123]
if (123 == values.forEach(e => {return e})){

currently, I'm getting an error:

values.forEach(e => {return e})) is not a function

ForEach doesn't return a value. The comparison needs to be done inside the callback. P.s. don't abbreviate or paraphrase errors when posting...always paste the error in full, and mention the line it occurs on if its not obvious — ADyson, Mar 20 '22 at 09:06

score 3 · Accepted Answer · answered Mar 20 '22 at 09:10

3

If i understand that you want, try something like this

let values = [1, 2, 3, 123]

if (values.includes(123)) {
   *do some code*
}

answered Mar 20 '22 at 09:10

Aaron Vasilev

score 2 · Answer 2 · answered Mar 20 '22 at 09:10

2

const array1 = [1,2,123,123];

array1.forEach(element => element === 123 && console.log(element));

answered Mar 20 '22 at 09:10

Ala

score 2 · Answer 3 · answered Mar 20 '22 at 09:14

You can use array.indexOf() function to check whether 123 is present in the array or not :

let values = [1, 2, 3, 123]

    if (values.indexOf(123)!=-1) {
       ...write code    
    }

let values = [1, 2, 3, 123]

if (values.indexOf(123)!=-1) {
   console.log("123 is present");
}else {
  console.log("123 is not present");
}

3 Answers3