the trait bound `&'a chain::Chain<'a>: Deserialize<'_>` is not satisfied

Question

I'm very new to rust and I want to access a parent struct from a children. I want to use Chain from its childs Chain.blocks. So I'm trying to store a reference to the parent Chain.

But I'm encountering this error.

the trait bound `&'a chain::Chain<'a>: Deserialize<'_>` is not satisfied
the following implementations were found:
  <chain::Chain<'a> as Deserialize<'de>>rustcE0277

This is my code.

// Chain
#[derive(Default, Serialize, Deserialize)]
pub struct Chain<'a> {
    pub blocks: Vec<Block<'a>>,
}

// Block
#[derive(Deserialize, Serialize)]
pub struct Block<'a> {
    pub id: String,
    pub prev_hash: String,
    pub timestamp: u64,
    pub nonce: i32,
    pub proof: String,
    pub miner: String,
    pub documents: Vec<String>,
    pub merkel_root: String,
    chain: &'a Chain<'a>,
}

impl<'a> Default for Block<'a> {
    fn default() -> Self {
        Self {
            ..Default::default()
        }
    }
}

Sorry if I reply too late.

Answer 1

Problems

What you're trying to make is a self-referential structure, which is troublesome in Rust. See these answers, for example. It's not necessarily impossible, but it would be best if you try to find a different model for your data.

Also: serde's derive mechanism doesn't care whether your field is pub or not, it will deserialize to it anyway. And it has no way to know that you want chain to contain a reference to its parent. In fact, it will generate a deserializer for block which can be used stand-alone. If you do wat @PitaJ suggests (chain: Box<Chain>), you'll get a deserializer that expects data like

{
  "id": "foo",
  …
  "merkel_root": "You're thinking of Merkle, Merkel is the German chancellor a. D.",
  "chain": {
    "blocks": [
      {
        "id": "bar",
        …
        "chain": {
          "blocks": []
        }
      }
    ]
  }
}

Lastly:

impl<'a> Default for Block<'a> {
    fn default() -> Self {
        Self {
            ..Default::default()
        }
    }
}

is infinite recursion. But rustc would have warned you about this if you'd managed to get past the compiler errors.

warning: function cannot return without recursing
  --> src/lib.rs:25:5
   |
25 |     fn default() -> Self {
   |     ^^^^^^^^^^^^^^^^^^^^ cannot return without recursing
26 |         Self {
27 |             ..Default::default()
   |               ------------------ recursive call site
   |

If you absolutely want this

… against better advice, then you can get something close with reference counting (and my favourite serde trick):

First, you need to solve the problem that serde won't know what to store in chain in Block. You could make it an Option and mark it #[serde(skip)], but I prefer having a second struct with only the fields you actually want to be deserialized:

#[derive(Deserialize)]
pub struct ChainSerde {
    pub blocks: Vec<BlockSerde>,
}

#[derive(Deserialize)]
pub struct BlockSerde {
    pub id: String,
    // … - doesn't contain chain
}

The actual struct you want to work with then looks like this

#[derive(Deserialize, Serialize, Debug)]
#[serde(from = "ChainSerde")]
pub struct Chain {
    pub blocks: Rc<RefCell<Vec<Block>>>,
}

#[derive(Debug, Serialize)]
pub struct Block {
    pub id: String,
    // …
    #[serde(skip)] // Serialization would crash without
    // If you wanted Chain instead of Vec<Block>, you'd need another
    // #[serde(transparent, from = "ChainSerde")]
    // struct ChainParent(Rc<RefCell<Chain>>)
    chain: Weak<RefCell<Vec<Block>>>,
}

Now, all you need to do is to tell serde how to turn the deserialized struct into the struct you actually want to work with.

impl From<ChainSerde> for Chain {
    fn from(t: ChainSerde) -> Self {
        let b: Rc<RefCell<Vec<Block>>> = Default::default();
        let bc: Vec<Block> = t
            .blocks
            .into_iter()
            .map(|block| Block {
                id: block.id,
                chain: Rc::downgrade(&b),
            })
            .collect::<Vec<Block>>();
        *RefCell::borrow_mut(&b) = bc;
        Chain { blocks: b }
    }
}

If you want to wait for Rust 1.60, you can do it a bit more neatly and without the RefCell by using Rc::new_cyclic:

#[derive(Deserialize, Debug)]
#[serde(from = "ChainSerde")]
pub struct ChainNightly {
    pub blocks: Rc<Vec<BlockNightly>>,
}

#[derive(Debug)]
pub struct BlockNightly {
    pub id: String,
    // …
    chain: Weak<Vec<BlockNightly>>,
}

impl From<ChainSerde> for ChainNightly {
    fn from(t: ChainSerde) -> Self {
        ChainNightly {
            blocks: Rc::new_cyclic(|blocks| {
                t.blocks
                    .into_iter()
                    .map(|block| BlockNightly {
                        id: block.id,
                        chain: blocks.clone(),
                    })
                    .collect()
            }),
        }
    }
}

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