Why my custom constructor is not called when an object is passed as a parameter?

Question

I have the following code:


struct Entity {
    Entity() {
        std::cout << "[Entity] constructed\n";
    }

    ~Entity() {
        std::cout << "[Entity] destructed\n";
    }

    void Operation(void) {
        std::cout << "[Entity] operation\n";
    }
};

void funcCpy(Entity ent) {
    ent.Operation();
}

int main() {
    Entity e1;

    funcCpy(e1);
}

This is the output:

[Entity] constructed
[Entity] operation
[Entity] destructed
[Entity] destructed

I expected my function to use the custom constructor, so the output would look like this:

[Entity] constructed
[Entity] operation
[Entity] constructed
[Entity] destructed
[Entity] destructed

Why does this happens? How could I use my custom constructor instead?

Thanks :)

`funcCpy(e1);` will call the copy constructor which you have not instrumented / implemented. Note in your output there is only 1 constructor call and 2 destructor calls. — Richard Critten, Apr 08 '22 at 10:20

score 0 · Accepted Answer · answered Apr 08 '22 at 10:23

0

https://en.cppreference.com/w/cpp/language/copy_constructor

object as params will call copy constructor of class

answered Apr 08 '22 at 10:23

Max Zhao

16
1

Why my custom constructor is not called when an object is passed as a parameter?

1 Answers1