I am building a clock but it keeps resetting every minute

Question

import os
import time

count = 0
minute = 0
hour= 0

day_week = 1            #this is for the NAME of the day
day_list = [" ", "Monday", "Tuesday", "Wednesday", "Thursday","Friday", "Saturday", "Sunday"]

month_day = 1           #this is for the NUMBER of the month
month_list = [" ", "January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"]
month_count = 1

year = 0

while True:
    for second in range(0,60):
        command = 'clear'
        if os.name in ('nt', 'dos'):
            command = 'cls'
        os.system(command)
        print(month_list[month_day], day_list[day_week], f"{hour:02d}", ":", f"{minute:02d}", ":", f"{second:02d}")
        if second == 59 :
            second = 0
            minute += 1

        elif minute == 59 :
            second = 0
            minute = 0
            hour += 1

        elif hour == 12 and count < 2 :
            second = 0
            minute = 0
            hour = 0
            count += 1
            hour += 1

        elif count == 2 :
            second = 0
            minute = 0
            hour = 0
            day_week += 1
            month_day += 1
            count = 0

        elif day_week == 7 :
            second = 0
            minute = 0
            hour = 0
            day_week = 1
            month_day += 1
            count = 0

        elif month_day == 28 and month_count == 2 :
            second = 0
            minute = 0
            hour = 0
            month_day = 1
            month_count += 1
            count = 0

        elif month_day == 29 and month_count == 2 and year/4 :
            second = 0
            minute = 0
            hour = 0
            month_day = 1
            month_count += 1
            count = 0

        elif month_day == 30 and month_count == 4 or 6 :
            second = 0
            minute = 0
            hour = 0
            month_day = 1
            month_count += 1
            count = 0
        elif month_day == 31 and month_count == 1 or 3 or 5 or 7 or 8 or 10 or 12 :
            second = 0
            minute = 0
            hour = 0
            month_day = 1
            month_count += 1
            count = 0

        elif month_count > 12 :
            second = 0
            minute = 0
            hour = 0
            month_day = 1
            month_count = 1
            count = 0


        time.sleep(1)

The problem seems to be coming from the part of the code between "month_day == 29" and "month_count > 12"

You can't write `month_count == 4 or 6` this way. Use e. g. `month_count in (4, 6)`. — Michael Butscher, Apr 20 '22 at 15:11
This doesn't answer your question but you should take a look at the *datetime* and/or *calendar* modules — DarkKnight, Apr 20 '22 at 15:17
Does this answer your question? [Why does "a == x or y or z" always evaluate to True?](https://stackoverflow.com/questions/20002503/why-does-a-x-or-y-or-z-always-evaluate-to-true) — Pranav Hosangadi, Apr 20 '22 at 15:28

score -1 · Answer 1 · answered Apr 20 '22 at 15:27

As pointed out by Michael Butscher problem is f.e. in this part of code:

elif month_day == 30 and month_count == 4 or 6 :
            second = 0
            minute = 0
            hour = 0
            month_day = 1
            month_count += 1
            count = 0

when you write statement like this python interprets it as

(month_day == 30 and month_count == 4) or 6

Where bool(6) = True (for every integer other than zero it returns true)

Therefore code in this if is executed in every iteretion, which you cant see because month_day is 1 as default and second is local for the scope of loop and after changing, it goes to next value in iterator and that's what you print. Also luckily minutes don't get set to zero at sec = 59 because first if statement is true therefore elifs are skiped

Adjust all expressions to sth more like:

month_day == 30 and month_count == 4 or month_count == 6

or:

 month_day == 30 and (month_count == 4 or month_count == 6)

and it may work better

of course `month_day == 30 and (month_count == 4 or month_count == 6)` is same as Michael's `month_count in (4, 6)` — piotre10, Apr 20 '22 at 15:28
As it’s currently written, your answer is unclear. Please [edit] to add additional details that will help others understand how this addresses the question asked. You can find more information on how to write good answers [in the help center](/help/how-to-answer). — Community, Apr 20 '22 at 18:48

I am building a clock but it keeps resetting every minute

1 Answers1