Regex: Extract digits separated by a hyphen

Question

What I have: 123456789-987654321
What I need: 3456789-4321 (keep last 7 digits from 1st group and keep last 4 digits from 2nd group)

(\d{7})-         gets me 3456789-
((\d{4})$(?<=))  gets me 4321

I can't figure out how to combine the 2 to get what I need.

This question should be closed due to the premises of having one match with skipped elements inside. Check it here: https://stackoverflow.com/questions/277547/regular-expression-to-skip-character-in-capture-group. — lemon, May 13 '22 at 16:26

The fourth bird · Answer 1 · 2022-05-13T16:11:58.637

0

You can match optional digits and then capture the 7 digits and the hyphen. Then match again optional digits and capture the last 4.

In the replacement use the 2 capture groups.

^\d*(\d{7}-)\d*(\d{4})$

edited May 13 '22 at 16:11

answered May 13 '22 at 15:19

The fourth bird

Thanks but I am limited to one expression in my system. – JenL May 13 '22 at 15:53
@JenL You can not skip characters for a single match. You could try using an alternation, but that will still give you 2 matches `\d{7}-|\d{4}$` https://regex101.com/r/7f2OPV/1 What is your "system"? – The fourth bird May 13 '22 at 15:55
System is BlackLine. – JenL May 13 '22 at 17:06
@JenL Is there some online documentation available related to the product using a regex? – The fourth bird May 13 '22 at 17:10

1 Answers1