Why won't my first if statement execute if the statement is true? Python

Question

I print my computer number so I can enter it into the player guess to make sure the value is true but when I enter it, it says the number is wrong. I am not sure why that is. Here is my code:


def start():

    computerNum = random.randint(1, 10)
    print(computerNum)
    playerGuess = input("Enter your guess: ")

    if playerGuess == computerNum:

        print("You got it! The number was " + str(computerNum))

    if playerGuess != computerNum:

        print("You are wrong, the number is " + str(computerNum))

startPlay = input("Would you like to play the game? ").lower()

if startPlay == 'yes':
    start()```

You are comparing an integer to a string. Cast one of them to the other. — kotatsuyaki, May 30 '22 at 15:04
*if playerGuess == str(computerNum)* is safest because it then doesn't matter if user input cannot be converted to *int* — DarkKnight, May 30 '22 at 15:10

score -1 · Answer 1 · answered May 30 '22 at 15:07

-1

cast computerNum to string or playerGuess to integer

answered May 30 '22 at 15:07

Csen

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Why won't my first if statement execute if the statement is true? Python

1 Answers1