for loop with zip in python

Question

I want to use zip to iterate to existing Lists.

I did that with the code below. Currently the output is just Name --> Name.

How do I use the new creates list or if that's not possible the other lists to print following sentence:

“#NAME is #AGE years old, and they can be called at #NUMBER”. Is it possible to accomplish this in a single loop?

    birth_years = {"Alice": "1990", "Bob": "1990", "Carol": "1995", "Felix":"1995","Max":"1995","Chris":"1998","Lea":"1998","Linn":"1998","Julia":"1998"}
    book = {"Alice": "+1554", "Bob": "+1885", "Carol": "+1006", "Felix":"+1604", "Max":"+1369","Chris":"+1882","Lea":"+1518","Linn":"+1742","Julia":"+1707"} 


   def test(birth_years, books):
      new_list = []
      for birth_year, book in zip(birth_years, books):
        new_list.append(f'{birth_year} -> {book}')
      return new_list

   print(test(birth_years,books))

Thanks!!

BR

score 1 · Accepted Answer · answered Jun 04 '22 at 09:10

1

zip is not the problem here. The problem is your for loop will simply loop over the keys in the dictionary, rather than the keys and values (see this answer)

The correct way of doing this is:

birth_years = {"Alice": "1990", "Bob": "1990", "Carol": "1995", "Felix":"1995","Max":"1995","Chris":"1998","Lea":"1998","Linn":"1998","Julia":"1998"}
books = {"Alice": "+1554", "Bob": "+1885", "Carol": "+1006", "Felix":"+1604", "Max":"+1369","Chris":"+1882","Lea":"+1518","Linn":"+1742","Julia":"+1707"} 


def test(birth_years, books):
    new_list = []
    for [name, birth_year], [unused, number] in zip(birth_years.items(), books.items()):
        new_list.append(f'{name} is {2022 - int(birth_year)} years old, and they can be called at {number}')
    return new_list

print(test(birth_years,books))

answered Jun 04 '22 at 09:10

justANewb stands with Ukraine

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Hey thanks for your answer. What is unused, number for? – Max Jun 04 '22 at 09:25
1

I name it unused because it is unused :). Specifically, both `name` and `unused` store the name. – justANewb stands with Ukraine Jun 04 '22 at 09:27
Is it also possible to something like this, that you won't get every name in the output? – Max Jun 04 '22 at 09:37
I just tried to implement name = input() but it doesn't work. Does it not work because "name" is already used? – Max Jun 04 '22 at 09:38
Then I tried something like for ___ in: \n: if name in birth_years \n:return new_list but it also does not work. Can you explain me maybe why? – Max Jun 04 '22 at 09:39
I used \n hier so that you know I didn't write it just next to each other. – Max Jun 04 '22 at 09:41
1

1) Yes, you can create a dict which key's are the names, and value are the string – justANewb stands with Ukraine Jun 04 '22 at 10:01
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2) you have to create the dict :) so you could use the input – justANewb stands with Ukraine Jun 04 '22 at 10:02

for loop with zip in python

1 Answers1