Remove duplicate from the nested Object of Array

Question

I am trying to remove the duplicate from the below array of Object which has some nested element with array

Below is my array.

      {
        field: ‘A’,
        value: {
          key_A: ['ajd', 'ajd', 'kajd'],
        },
      },
      {
        field: ‘A’,
        value: {
          key_B: ['123', '4', '45', '94'],
        },
      },
      {
        field: 'A',
        value: {
          key_A: ['ajd', 'ajd', ''],
        },
      },
      {
        field: ‘A’,
        value: {
          key_B: ['123', '4', '45'],
        },
      },
      {
        field: ‘Z’,
        value: {
          key_A: ['ajdm', 'askjd', 'kajd'],
        },
      },
      {
        field: ‘Z’,
        value: {
          key_B: ['13', '123', '1823'],
        },
      },
      {
        field: ‘Z’,
        value: {
          key_A: ['ajdm', 'askjd', ''],
        },
      },
      {
        field: ’Z’,
        value: {
          key_B: ['13', '123', ''],
        },
      },
    ];

and I want to keep the 1st key under each field i.e 1st key_A under field 'A' and 1st key_B under field 'A'

same for field 'Z'

so final o/p:

      {
        field: ‘A’,
        value: {
          key_A: ['ajd', 'ajd', 'kajd'],
        },
      },
      {
        field: ‘A’,
        value: {
          key_B: ['123', '4', '45', '94'],
        },
      },
      {
        field: ‘Z’,
        value: {
          key_A: ['ajdm', 'askjd', 'kajd'],
        },
      },
      {
        field: ‘Z’,
        value: {
          key_B: ['13', '123', '1823'],
        },
      },
    ];

I tried some logic with filter looping over the array but for the nested could not figure out a logic.

score 1 · Accepted Answer · answered Jun 13 '22 at 14:40

A possible implementation using the answer provided here. the findIndex gives the index of first element that satisfies the condition and the filter therefore filters out the first elements that satisfies the condition.
Object.keys(t.value)[0] gives either "key_A" or "key_B" depending on the element

let arr =    [  {        field: 'A',        value: {          key_A: ['ajd', 'ajd', 'kajd'],        },      },      {        field: 'A',        value: {          key_B: ['123', '4', '45', '94'],        },      },      {        field: 'A',        value: {          key_A: ['ajd', 'ajd', ''],        },      },      {        field: 'A',        value: {          key_B: ['123', '4', '45'],        },      },      {        field: 'Z',        value: {          key_A: ['ajdm', 'askjd', 'kajd'],        },      },      {        field: 'Z',        value: {          key_B: ['13', '123', '1823'],        },      },      {        field: 'Z',        value: {          key_A: ['ajdm', 'askjd', ''],        },      },      {        field:'Z',        value: {          key_B: ['13', '123', ''],        },      },    ];

let res = arr.filter((v, i, self) =>
  i === self.findIndex((t) => (
    t.field === v.field && Object.keys(t.value)[0] === Object.keys(v.value)[0]
  ))
)

console.log(res)

.as-console-wrapper { max-height: 100% !important; top: 0; }

I had seen the exact solution and even tried the same just missed the [0] there. Thanks — Bishal Jain, Jun 13 '22 at 15:35

score 0 · Answer 2 · answered Jun 14 '22 at 00:08

Something like this should do it.

interface Address {
    address: string,
    city: string,
    state: string,
    zip: number
}

const addresses: Address[] = [
    {
        address: "1234 Main St",
        city: "San Diego",
        state: "CA",
        zip: 92014
    },
    {
        address: "4444 Main St",
        city: "San Diego",
        state: "CA",
        zip: 92014
    },
    {
        address: "5555 Main St",
        city: "San Diego",
        state: "CA",
        zip: 92014
    },
    {
        address: "6666 Main St",
        city: "San Diego",
        state: "CA",
        zip: 92014
    },
    {
        address: "7777 Main St",
        city: "San Diego",
        state: "CA",
        zip: 92014
    }
]

function delay(time: number) {
    return new Promise(resolve => setTimeout(resolve, time));
  }


const apiCaller = async(addr: Address) => { 
    await delay(0.5);
    return `Got ${addr.address}`
}

const apiRunner = async () => {
    const results: PromiseSettledResult<string>[] = [];

    let promises: Promise<string>[] = [];

    for (const address of addresses) {
        promises.push(apiCaller(address));
        if (promises.length >= 10) {
            const rez = await Promise.allSettled(promises);
            results.push(...rez);
            promises = [];
        }
    }

    if (promises.length > 0) {
        const rez = await Promise.allSettled(promises);
        results.push(...rez);
    }

    return results;

}

Remove duplicate from the nested Object of Array

2 Answers2