how to get out of inner loop without breaking

Question

so I am working on this program and I am trying to remove duplicates from an array and I wanna leave the inner loop and go back to the outer loop after every iteration but I don't want the inner loop to start over because now everytime I break out of the inner loop the next iteration the inner loop starts all over again so num is always 1

 def removeDuplicates(self, nums: List[int]) -> int:
    for i in range(len(nums)-1):
        curr = nums[i+1]
        for num in nums:
            if num == curr:
                print('removed ' , num)
            break

The inner loop is always going to find a match, since it's just checking whether an element of the list is in the same list. It's not checking for duplicates, because it doesn't skip its own index. — Barmar, Jun 13 '22 at 21:24
@Barmar current is the next number after num so its skipping and looking at the one after it — rawan arafat, Jun 13 '22 at 21:26
@rawanarafat is it mandatory that you print every removed element ? Or do you only have to remove the duplicates, and printing was just there for debug ? — vultkayn, Jun 13 '22 at 21:27
@vultkayn no I am just doing it to make sure I am removing the right elements — rawan arafat, Jun 13 '22 at 21:28
@rawanarafat But the inner loop doesn't skip it, it loops over the entire list, including `i+1`, which is `current`. — Barmar, Jun 13 '22 at 21:28

score 0 · Accepted Answer · answered Jun 13 '22 at 21:29

0

Simply use a set then

nums = list(set(nums))

answered Jun 13 '22 at 21:29

vultkayn

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Any time the answer is this simple, it's a duplicate somewhere. – Makoto Jun 13 '22 at 21:35
1

Noted for next time – vultkayn Jun 13 '22 at 21:37

how to get out of inner loop without breaking

1 Answers1