Flutter - Why is Future returning "Instance of Future" and not the data from my php file

Question

Here is the Future function that should return the data in my php file

    Future displayLg_name() async {
        var url = Uri.http(
            "192.168.68.216", '/ump_attendance_2/username.php', {'q': '{http}'});
        var response = await http.post(url, body: {
          "lg_username": username.lg_username,
        });
        if (response.body.isNotEmpty){
          return (json.decode(response.body));
        };

I'm trying to display it in my container

   Container(
          alignment: Alignment.centerLeft,
          child: Text(
            displayLg_name().toString(),
            style: TextStyle(
              color: Colors.black54,
              fontFamily: "Ubuntu",
              fontWeight: FontWeight.bold,
              fontSize: scrwidth / 18,
            ),
          ),
        ),

And here is my php file

            <?php
            include ("config.php");
            session_start();
            $lg_username = $_REQUEST['lg_username'];

            $sql = "SELECT lg_name FROM hr_login WHERE lg_username = '$lg_username'";

            $res = mysqli_query($conn,$sql);

            if (mysqli_num_rows($res)>0){
                while($row = mysqli_fetch_assoc($res)){
                    echo json_encode($row['lg_name']);
                }
            }
            ?>

I'm guessing there's nothing wrong with my php file but somewhere in flutter .dart

Thanks in advance

**Warning:** You are wide open to [SQL Injections](https://php.net/manual/en/security.database.sql-injection.php) and should use parameterized **prepared statements** instead of manually building your queries. They are provided by [PDO](https://php.net/manual/pdo.prepared-statements.php) or by [MySQLi](https://php.net/manual/mysqli.quickstart.prepared-statements.php). Never trust any kind of input! Even when your queries are executed only by trusted users, [you are still in risk of corrupting your data](http://bobby-tables.com/). [Escaping is not enough!](https://stackoverflow.com/q/32391315) — Dharman, Jun 20 '22 at 10:40
my bad. I accidentally put to much attention to solve error in flutter.. thanks for letting me know! — Jasmirulnaim, Jun 21 '22 at 01:26

belinda.g.freitas · Accepted Answer · 2022-06-20T16:58:01.450

Try to do something like this instead:

var text = await displayLg_name();
/* ... */
Container(
  alignment: Alignment.centerLeft,
  child: Text(
    text ?? '',
    style: TextStyle(
      color: Colors.black54,
      fontFamily: "Ubuntu",
      fontWeight: FontWeight.bold,
      fontSize: scrwidth / 18,
    ),
  ),
),

Edited
If your class is statefull, you can declare it inside initState() like this:

var text;

void _init() async {
  await displayLg_name().then((value) => setState(() => text = value));
}

@override
void initState() {
  super.initState();
  _init();
}

Flutter - Why is Future returning "Instance of Future" and not the data from my php file

1 Answers1