How to make while loop run when a variable returns false?

Question

My code works without errors however if I type something random it still continues and does not print "Error" and rerun the code? How would I fix this?

gender = True
while gender == True:
    gender = input("Enter Gender: ")
    if gender == "Male" or "male" or "Female" or "female" :
        gender = False
    else:
        print("Error")
        gender = True

Cardstdani · Answer 1 · 2022-06-25T16:22:23.263

-1

You can use lower() and a correct if statement condition to fix the output error:

gender = True
while gender == True:
    gender = input("Enter Gender: ").lower()
    if gender in {"female", "male"}:
        gender = False
    else:
        print("Error")
        gender = True

edited Jun 25 '22 at 16:22

answered Jun 25 '22 at 15:54

Cardstdani

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No, no, no, no that is NOT the problem ... – azro Jun 25 '22 at 15:59
+ that’s not a dictionary – 0x263A Jun 25 '22 at 16:01
@azro What do you mean with your comment? – Cardstdani Jun 25 '22 at 16:07
1

you said "use lower to fix" : no, the error is not about lower/upper. It's about operator precedence , as the duplicate link points out – azro Jun 25 '22 at 16:20
@azro You're right, I'm going to edit the question – Cardstdani Jun 25 '22 at 16:21
azro - would you be able to show me how you would run this code without using .lower() – Tan7 Jun 25 '22 at 16:21
@Tan7 did you read https://stackoverflow.com/questions/20002503/why-does-a-x-or-y-or-z-always-evaluate-to-true ? the duplicate that we point out – azro Jun 25 '22 at 16:23
I just looked at that. Thank you – Tan7 Jun 25 '22 at 16:25

How to make while loop run when a variable returns false?

1 Answers1