My Javascript code always returns 10 or 11 and never returns the other random numbers which have not been specified in the if condition

Question

This is my Javascript code:

function getRandomCard(){
        randomCard = Math.floor(Math.random()*13)+1
    
        if (randomCard === 1){
            return 11
        }
        
        else if (11 <= randomCard <= 13){
            return 10   
        }
    
        else{
            return randomCard
        }
    }
    
 console.log(getRandomCard())

I have linked it to an HTML file with a button to call this function on getting clicked. Every time it is, it only returns 10 or 11. What could be wrong with my code?

`11 <= randomCard <= 13` doesn't work in JavaScript, use `11 <= randomCard && randomCard <= 13` — Nick is tired, Jun 29 '22 at 06:49
@NickstandswithUkraine It [works](https://stackoverflow.com/questions/4089284/why-does-0-5-3-return-true) BUT not in a way one would expect. OP needs to use the `&&` operator like you suggested. — Yousaf, Jun 29 '22 at 06:58
@Yousaf That depends on your definition of work :p, but yes, I'm aware, I was the one that voted to close. — Nick is tired, Jun 29 '22 at 07:07
@NickstandswithUkraine Your comment suggested that `11 <= randomCard <= 13` is syntactically wrong. Anyways, I didn't notice that you had voted to close the question. — Yousaf, Jun 29 '22 at 07:09
@Yousaf What is actually happening in my code then? If you could please let me know. — Afif Mohammed Varikkodan, Jun 30 '22 at 07:06
`11 <= randomCard <= 13` - this expression is evaluated from left to right. FIrst `11 <= randomCard` is evaluated. It will evaluate to a boolean value (either true or false). So the expression is reduced to `true <= 13` or `false <= 13`. As you are comparing boolean value with a number, boolean value is converted into a number (true -> 1, false -> 0). At the end you are comparing either `1 <= 13` or `0 <= 13` which evaluates to true. — Yousaf, Jun 30 '22 at 07:12

Ravi Makwana · Accepted Answer · 2022-06-29T13:09:43.647

1

Not sure maybe your if condition is wrong..

function getRandomCard(){
        randomCard = Math.floor(Math.random()*13)+1
    
        if (randomCard === 1){
            return 11
        }
        
        else if (11 <= randomCard && randomCard <= 13){
            return 10   
        }
    
        else{
            return randomCard
        }
    }
    
 console.log(getRandomCard())

edited Jun 29 '22 at 13:09

answered Jun 29 '22 at 06:52

Ravi Makwana

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My Javascript code always returns 10 or 11 and never returns the other random numbers which have not been specified in the if condition

1 Answers1