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How to compare the value in a string list with another value in a string list and if I do succeed in comparing with 2 of the lists, how can I store a new value in a new list if the value in the string lists is matches?

def start_game():
    food_list = ["salad", "steak", "fries", "rice", "noodles", "fruits"]
    random_food_list = [random.choices (food_list, k = 4)]
    player_guess_list = []
    correct_guess_list = []

    for i in range(1,5):
        player_guess = input("food" + str(i) + ":").lower()
        if player_guess not in food_list:
            print("Invalid foods, Restart Again")
            start_game()
        else:
            player_guess_list.append(player_guess)
    print(player_guess_list) # For review
    print(random_food_list) # For review

For example:

User input list = [salad, steak, noodles, rice]
randomized list = [salad, rice, salad, rice]
correct_guess_list = [O,X,X,O]

Output

Correct food in correct place: 2
Correct food in wrong place: 2
Kurumi3
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4 Answers4

4

You can do what you by using a single list comprehension of the values in the two list zipped together.

food_list = ["salad", "steak", "fries", "rice", "noodles", "fruits"]
#random_food_list = random.choices(food_list, k = 4)
random_food_list = ['salad', 'rice', 'salad', 'rice']  # Hardcode for testing.

correct_guess_list = ['O' if f1.lower() == f2.lower() else 'X'
                        for f1, f2 in zip(food_list, random_food_list)]

print(correct_guess_list)  # -> ['O', 'X', 'X', 'O']

correct_food_in_correct_place = correct_guess_list.count('O')
correct_food_in_wrong_place = correct_guess_list.count('X')

print(f'Correct food in correct place: {correct_food_in_correct_place}')  # -> 2
print(f'Correct food in wrong place: {correct_food_in_wrong_place}')  # -> 2
martineau
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  • Thank you for your response sir, I am still new to python so I didint think of that. Thank you very much T,T – Kurumi3 Jun 29 '22 at 20:40
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    It would not be reasonable to expect you to think of doing things this way at this point — that's where Stack Overflow can help. – martineau Jun 29 '22 at 20:47
3

The question is quite unclear. The example looks like you want to compare two lists and create a third list that stores where the first two lists are identical.

This can be done this way:

user_input_list = ["salad", "steak", "noodles", "rice"]
randomized_list = ["salad", "rice",  "salad",   "rice"]
  
new_list = list(map(lambda x, y : 'O' if x == y else 'X', \
                    user_input_list,                      \
                    randomized_list))
   
correct_food_in_correct_place = new_list.count('O')
correct_food_in_wrong_place = new_list.count('X')

print(new_list)
print(correct_food_in_correct_place)
print(correct_food_in_wrong_place)

Sorry, that is already quite heavy Python code. Not really easy for beginners. Try it out and you will see what it does. If this does not answer your question, please ask ask more concretely and try to isolate your problem a bit.

habrewning
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  • My bad sir, since my English is not really good haha. This kind of exercise just came out of my mind. So i am here seeking for advice since i am stuck. However, I would love to learn about lambda function after I try some multiple projects. – Kurumi3 Jun 29 '22 at 20:38
2

One problem I see in your anser is you are creating a list of list rather than list to compare with in the first place random.choices (food_list, k = 4) returns a list so no need to enclose it in square brackets. Now both the types will be list and you can use indexing to compare values from both list.

import random
def start_game():
    food_list = ["salad", "steak", "fries", "rice", "noodles", "fruits"]
    random_food_list = random.choices (food_list, k = 4)
    player_guess_list = []

    correct_guess_list = []

    for i in range(1,5):
        player_guess = input("food" + str(i) + ":").lower()
        if player_guess not in food_list:
            print("Invadlid foods, Restart Again")
            start_game()
        else:
            player_guess_list.append(player_guess)

    print(player_guess_list) # For review
    
    print(random_food_list) # For review
    for i in range(0 , len(random_food_list)):
        if random_food_list[i] == player_guess_list[i]:
            correct_guess_list.append(random_food_list[i])
    print(correct_guess_list)
start_game()
Sanket Wagh
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  • ohhhh no wonder, i keep getting error range out of keywords or other errors. Thank you very much sir! – Kurumi3 Jun 29 '22 at 20:34
2

I made the correct guesses list using a list comprehension:

correct_guess_list = ["O " if random_food_list[player_guess_list.index(food)] == food else "X" for food in
                          player_guess_list]

Full code:

import random


def start_game():
    food_list = ["salad", "steak", "fries", "rice", "noodles", "fruits"]
    random_food_list = random.choices(food_list, k=4)
    player_guess_list = []
    correct_guess_list = []
    correct_guesses = 0

    for i in range(1, 5):
        player_guess = input("food" + str(i) + ":").lower()
        if player_guess not in food_list:
            print("Invalid foods, Restart Again")
            start_game()
        else:
            player_guess_list.append(player_guess)
            if player_guess_list[i-1] == random_food_list[i-1]:
                correct_guesses += 1
        print(player_guess_list)  # For review
        print(random_food_list)  # For review
    correct_guess_list = ["O " if random_food_list[player_guess_list.index(food)] == food else "X" for food in
                          player_guess_list]
    print(correct_guess_list)
    print(f"Food in correct place: {correct_guesses}")
    print(f"Food in incorrect place: {4 - correct_guesses}")


start_game()
Raed Ali
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  • Wow, this is interesting. I run the code and it is as smooth as butter. Looks like i gonna learn list comprehension. Thank you very much kind sir T.T – Kurumi3 Jun 29 '22 at 20:35