Create two identical object with different value javascript

Question

i have to create 2 identical object, one with value 'home' and other with value 'mailing' if the condition is true I send them both otherwise I send only 'home', what can I do?

it's correct to do that?

var arrayObj = []
var reqBodyAddress = {};
    
    reqBodyAddress.startDate = new GlideDateTime(current.u_data_inizio_contratto).getNumericValue();
    reqBodyAddress.addressType = function(){
    var objAddressType1 = {
            home:'home'
        }
    var objAddressType2 = {
            mailing:'mailing'
        }
        if(current.u_domicilio == true){
            reqBodyAddress.addressType = objAddressType1 + objAddressType2;
            }else{
            reqBodyAddress.addressType = objAddressType1;
        }
    };

arrayObj.push(reqBodyAddress);

var sReqBodyData = JSON.stringify(arrayObj);

Then you need to edit the question to explain how. The only other thing I can think of that you might mean is that instead of one combined object you would want to send both individual objects, which would be `[objAddressType1, objAddressType2]`. Either way, please edit your question to clarify your needs. — Jared Smith, Jul 06 '22 at 15:08

mehrab safdel · Answer 1 · 2022-07-06T15:24:43.890

use this

reqBodyAddress.addressType = {
                home:'home'
            ...(current.u_domicilio && {mailing:'mailing'})

}

it's more readable first, and work correct. try to use const and let and avoid to use var for declaring variable in your js code.

your addressType property must get an object for value, right? so why do you use function for its value? also you can't merge two object with + operator. i hope this code solve your problem.

Brother58697 · Accepted Answer · 2022-07-06T15:51:53.830

Use Object.assign(target, ...sources) [read more] which copies multiple source objects into a target object, and then use a condition on the second object. similar to this:

let a = {foo:'foo'}
let b = {bar:'bar'}

let c = Object.assign(a, (false? b : null));
console.log(c) // {foo:"foo"}

let d = Object.assign(a, (true? b : null));
console.log(d) // {foo:"foo", bar:"bar"}

Test it here

For your case, it would look like this:

reqBodyAddress.addressType = function(){
  var objAddressType1 = {
    home:'home'
  }
  
  var objAddressType2 = {
    mailing:'mailing'
  }
  
  reqBodyAddress.addressType = Object.assign(
    objAddressType1, // target
    (current.u_domicilio?  objAddressType2 : null) // source
  )
}

Note that this doesn't return a copy and will edit the target object. If you don't want to edit any objects when using this function, you can make your target an empty object {} and put all your objects as sources like this:

reqBodyAddress.addressType = function(){
  var objAddressType1 = {
    home:'home'
  }
  
  var objAddressType2 = {
    mailing:'mailing'
  }
  
  reqBodyAddress.addressType = Object.assign(
    {}, // empty target
    objAddressType1, // source 1
    (current.u_domicilio?  objAddressType2 : null) // source 2
  )
}

Create two identical object with different value javascript

2 Answers2