-2
number = [1, 1, 2, 2, 3, 3, 4, 4, 5, 5, 5, 4, 4, 3, 3, 2, 2, 1, 1]
 
number.reverse()
        for element in number:
            if number.count(element) > 1:
                number.remove(element)

 number.reverse()

# when I execute this program for this particular list the duplicates are not removed why?
John Gordon
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Yogesh Giri
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    Don't remove items from a list while you're iterating over the list. Confusing things happen, just like this. – John Gordon Jul 08 '22 at 02:35
  • removing items from a list while iterating over it would make iterations shorter and may not go through entire list. – vman Jul 08 '22 at 02:37

1 Answers1

2

use set

number = [1, 1, 2, 2, 3, 3, 4, 4, 5, 5, 5, 4, 4, 3, 3, 2, 2, 1, 1]
print(set(number))

output is {1, 2, 3, 4, 5}

John Beats
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