Rounding up to two limits in Python

Question

I am trying to round up to nearest 10 for Max and Min. However, for Max, the nearest 10 should be greater than Max and for Min, the nearest 10 should be less than Min. The current and the expected outputs are presented.

import numpy as np
Max = [99.91540553]
Min = [8.87895014]
Amax=round(Max[0],-1)
Amin=round(Min[0],-1)

The current output is

Amax=100
Amin=10.0

The expected output is

Amax=100
Amin=0.0

Does this answer your question? [floor and ceil with number of decimals](https://stackoverflow.com/questions/58065055/floor-and-ceil-with-number-of-decimals) — Joooeey, Jul 15 '22 at 15:33

snoopyhunter · Accepted Answer · 2022-07-15T15:25:03.323

2

If I understand your question correctly, you'd need the floor and ceil functions from the math module.

import math as m
Max = [99.91540553]
Min = [8.87895014]
Amax = 10*m.ceil(Max[0]/10)
Amin = 10*m.floor(Min[0]/10)

These also exist in numpy if you would like to perform this on every element in a numpy array:

import numpy as np
Max = np.array([99.91540553, 95.7, 93.2])
Min = np.array([8.87895014, 15.7, 17.2])
Amax = 10*np.ceil(Max/10)
Amin = 10*np.floor(Min/10)

edited Jul 15 '22 at 15:25

answered Jul 15 '22 at 15:17

snoopyhunter

95
8

1

Thanks Murali, I forgot to divide by 10. – snoopyhunter Jul 15 '22 at 15:20

score 2 · Answer 2 · answered Jul 15 '22 at 15:22

You can use math.floor and math.ceil, these functions round only to units so we just divide by ten and then multiply by ten to round to tens.

import math
Max = [99.91540553]
Min = [8.87895014]
Amax= 10*math.ceil(Max[0]/10)
Amin= 10*math.floor(Min[0]/10)
print(Amax, Amin)

Output

100 0

Rounding up to two limits in Python

2 Answers2

Output