I writing code to make marksheet of 10th class. there is fourth scanf is not taking input

Question

My fourth scanf is not taking input?

I'm trying to make mark sheet in c language. Then my first three scanf run properly but my fourth scanf is not taking input my program is directly stop executing.

#include<stdio.h>
int main(){
    int subject, mathematics, english, hindi, science, socialScience;
    char school[50];
    char name[50];
    char section[5];
    int standard;
    int total;

    printf("\nPlease Enter your school name: ");
    scanf("%[^\n]%*c", school);

    printf("\nEnter student name: ");
    scanf("%[^\n]%*c", name);

    printf("\nenter standard: ");
    scanf("%d", &standard);

    printf("\nenter your section:");
    scanf("%[^\n]%*c", section);
    
    return 0;
}

Does this answer your question? [scanf() leaves the newline character in the buffer](https://stackoverflow.com/questions/5240789/scanf-leaves-the-newline-character-in-the-buffer) — Gerhardh, Jul 29 '22 at 08:21
The general advice around here when it comes to `scanf` is: Forget that it exists. Use `fgets` to read lines, and then possibly `sscanf` to parse the lines. — Some programmer dude, Jul 29 '22 at 08:22
Side note: If you use `scanf` or `sscanf` etc., you should always check return value. Also, if you don't have a `\n` at the end of your output, you might not see it due to line buffering of `stdout`. If you don't want `\n` because you want to get the input in same line, you can use `fflush(stdout);` after your `printf` calls. — Gerhardh, Jul 29 '22 at 08:23
Instead of trying to kludge away the newline with `scanf("%[^\n]%*c", school);` you must filter out any *leading* newline with `scanf(" %[^\n]", school);` with an added space. This is how the function is intended to be used. Please see [scanf() leaves the newline char in the buffer](https://stackoverflow.com/questions/5240789/scanf-leaves-the-new-line-char-in-the-buffer). — Weather Vane, Jul 29 '22 at 08:24
`scanf("%d", &standard);` - ask yourself what is left in the input stream immediately *after* that happens. Consider every keystroke you hit; *every single keystroke*. What did you hit after you finished the last digit of `standard` ? Now, what causes the next `scanf` to *stop* parsing its first argument? — WhozCraig, Jul 29 '22 at 08:24
You must also restrict the input length, escpecially with a tiny buffer like `char section[5];` with `scanf(" %4[^\n]", section);` — Weather Vane, Jul 29 '22 at 08:27
Begin again. You've already instantiated lots of variables when you encounter a problem. "Incremental Development"... As others have said, shun `scanf()` and use `fgets()` to load into a general purpose buffer that you can `strncpy()`. Get one field working before moving on to the next. Use `val = atoi(buffer)` instead of `scanf("%d")... — Fe2O3, Jul 29 '22 at 08:34

score 0 · Answer 1 · answered Jul 29 '22 at 09:27

0

Add a getchar() after the 3rd scanf(). But as other have suggested, please move to fgets().Check this answer for explanation

answered Jul 29 '22 at 09:27

NeilB

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I writing code to make marksheet of 10th class. there is fourth scanf is not taking input

1 Answers1