How to nest loops N number of times python

Question

I'm creating a program, which needs to nest loops N number of times. Is there any way to do this? Or do I need to do it manually?

Wanted result:

for i in range(N):
    #Do something
    for i in range(N-1):
        #Do something
        for i in range(N-2):
            #Etc, continues until the value in range is 0

What do you need N nested loops for? Most likely there is a way to do that without using N nested loops. — mkrieger1, Jul 29 '22 at 21:09
Maybe [`itertools.product`](https://docs.python.org/3.8/library/itertools.html#itertools.product) ? — Andrej Kesely, Jul 29 '22 at 21:10
@mkrieger1 I'm creating a tic tac toe ai, which manually loops through all the possible ways, and chooses the best way to win (I'm doing this for a challenge so this has to be the way it gets its moves). — Ebrahim Momin, Jul 29 '22 at 21:11
@AndrejKesely from the examples the docs are giving, I don't think it would work — Ebrahim Momin, Jul 29 '22 at 21:14
@EbrahimMomin Better edit your question and put there small example of the problem and expected output. — Andrej Kesely, Jul 29 '22 at 21:14
@AndrejKesely done. Would iterables.product be able to do this task? — Ebrahim Momin, Jul 29 '22 at 21:18
This reads like it might be trying to do the same as `itertools.permutations`. — Nobody moving away from SE, Jul 29 '22 at 21:34

Dmiich · Accepted Answer · 2022-07-29T21:27:17.953

3

You can do that with recursion

def func(N)
    if N == 0: return
    for i in range(N):
        #do something
    return func(N-1)

edited Jul 29 '22 at 21:27

answered Jul 29 '22 at 21:22

Dmiich

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How to nest loops N number of times python

1 Answers1