create a dataframe with a column that has %

Question

I would like to create a dataframe like these

State	% religious
QLD	20
NSW	12
WA	10
TAS	8
SA	11
VIC	15
NT	22
ACT	18

I gave that code

religious <- data.frame(
  stringsAsFactors = FALSE,
  State = c("QLD", "NSW","WA","TAS","SA","VIC","NT","ACT"),
  % religious  = c( 20,12,10,8,11,15,22,18)
)

But when i gave % religious it comes error message?

But I think something is wrong with my wifi connection, it was because of that — , Aug 01 '22 at 13:57

score 0 · Accepted Answer · answered Aug 01 '22 at 13:55

You'll need to put the irregular name in quotes and then turn off the automatic code that translates column names to valid R variables.

religious <- data.frame(
  stringsAsFactors = FALSE,
  State = c("QLD", "NSW","WA","TAS","SA","VIC","NT","ACT"),
  "% religious"  = c( 20,12,10,8,11,15,22,18),
  check.names = FALSE
)

create a dataframe with a column that has %

1 Answers1