One line code for Converting list to dictionary values

Question

Is there a one liner code for converting the following list/string to map, basically counting all chars and storing in map.

lst = 'leet'

map ={'l':1,'e':2,'t':1}

what i did so far

for i in lst:
    if i not in map:
        map[i] = 1
    else:
        map[i]+=1

score 2 · Accepted Answer · edited Aug 16 '22 at 02:38

2

Try

>>> from collections import Counter
>>> Counter("leet")
Counter({'e': 2, 'l': 1, 't': 1})

edited Aug 16 '22 at 02:38

rv.kvetch

answered Aug 16 '22 at 02:36

Jeffrey Ram

score 1 · Answer 2 · answered Aug 16 '22 at 02:39

1

from collections import Counter; c = Counter(lst) since you said must be one-liner :)

answered Aug 16 '22 at 02:39

mj_codec

score 0 · Answer 3 · answered Aug 16 '22 at 02:37

0

{letter: "leet".count(letter) for letter in "leet"} might work

answered Aug 16 '22 at 02:37

thebadgateway

it does, but the `str.count` is a little bit inefficient when a letter is repeated multiple times in a str. also the `list()` constructor can be removed in this case. – rv.kvetch Aug 16 '22 at 02:40

3 Answers3