If I enter: 'I love stack overflow', how can I print first&second&third letter from this string.
The output to be like this:
'Ilso', 'otv', 'vae', 'ecr'...
If anyone can help me with this would be great! Thanks :D
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2You mean you want to print all first, second and third letters of each word, not of the whole string. Look into `str.split`, `str.join` and `itertools.zip_longest`. – Jan Christoph Terasa Aug 23 '22 at 09:47
3 Answers
2
Solution
Use str.split, str.join and itertools.zip_longest:
from itertools import zip_longest
s = 'I love stack overflow'
result = [''.join(chars) for chars in zip_longest(*s.split(), fillvalue='')]
print(result)
# ['Ilso', 'otv', 'vae', 'ecr', 'kf', 'l', 'o', 'w']
Explanation
s.split() splits the string into a list of words, seperated by space. zip_longest returns tuples of characters from all words, filling up the missing values (for short words) with the empty string ''. ''.join() concatenates (adds) the characters to a new string. The list comprehension loops over all the letter tuples, first letter, second, etc.
Jan Christoph Terasa
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string = 'I love stack overflow'
words = string.split()
longest_word = len(max(words, key=len))
result = [
''.join([
word[index]
for word in words
if len(word) > index
])
for index in range(longest_word)
]
print(result)
Igor Dragushhak
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This can be the solution
a='I love stack overflow'
l=a.split()
for i in range(len(max(l,key=len))):
b=''
for j in l:
try:
b=b+j[i]
except Exception:
pass
print(b)
rektifyer
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1If you mean to catch an `IndexError`, then catch it specifically. Also, I suspect you'd want to `break` instead of keep `pass`ing on more exceptions that'll inevitably occur past the last valid index? – AKX Aug 23 '22 at 10:07
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The second loop actually iterates through the list of words in a string. So if I break instead of the pass then the loop will stop on the second character. – rektifyer Aug 23 '22 at 10:57