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Is there a way to only get the url when using youtube-dl or yt-dlp embedded in python code?

It seems that --get-url is not in the YoutubeDL class' available options.

I tried i think all logical way to pass --get-url, e.g. geturl, getUrl, get_url, ...

There must be a way since the executable can do it. I wanted to "reverse engineer" it but the code execution order is kinda hard to track since I don't know python very well.

5th
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1 Answers1

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Ok I think I found out and I think it's the intended way to do it.

I just thought that I should be able to directly pass the same flag as a class option, since most of them have the same name, turns out --get-url is just an "alias" for:

options = {
  "quiet":    True,
  "simulate": True,
  "forceurl": True,
}

The more you know.

Also, you can use extract_info(url) instead of download([url]), like so:

with youtube_dl.YoutubeDL(options) as ytdl:
  info = ytdl.extract_info("https://twitter.com/MissMikkaa/status/1568324392953827328")
  url = info["url"]

Hope it can help somebody else in the future :)

5th
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