how is the pointer arithmetic operator ++ work in C?

Question

is ++ in c pointer is a kind of operator overloading ,which similar to C++? i wonder how this pointer arithmetic work?

#include <stdio.h>
int main(){
  int i[5]={1,2,3,4,5};                 int    *pi=i;
  double f[5]={1.0,2.0,3.0,4.0,5.0};    double *pf=f;

  printf("sizeof int:%lu bytes\tsizeof double:%lu bytes\t\n"
         ,sizeof (int),sizeof (double ));
  printf("i[0]: %d \tMemAddress:%p\t\n",*pi,pi);
  printf("i[1]: %d \tMemAddress:%p\t\n",*++pi,pi);
  printf("f[0]: %f \tMemAddress:%p\t\n",*pf,pf);
  printf("f[1]: %f \tMemAddress:%p\t\n",*++pf,pf);
}

Try reading Chapter 5 of K&R. It should give you most of the answers you are looking for. — cup, Oct 03 '22 at 06:55
Pointers are just numbers, the `++` operator works the same as it does for any other numeric type (other than it increments by the size of the pointed to type rather than by 1) — Alan Birtles, Oct 03 '22 at 06:59
This has absolutely nothing to do with operator overloading and also works the same in C and C++. — Lundin, Oct 03 '22 at 07:30
https://stackoverflow.com/questions/394767/pointer-arithmetic — mmixLinus, Oct 03 '22 at 07:50

score 1 · Accepted Answer · edited Oct 03 '22 at 11:55

1

++-ing / ---ing a pointer in C adds or subtracts sizeof(the type that pointer points to) to the pointer.

e.g.

Assume that an int takes up 4 bytes in memory, and there's an int pointer named p that points to some memory address, like 0x10000000. p++ will cause p to point to 0x10000004.

edited Oct 03 '22 at 11:55

q2333

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answered Oct 03 '22 at 06:58

F1yingC0der

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how is the pointer arithmetic operator ++ work in C?

1 Answers1