How to write a macro to convert member function to a string of its name?

Question

I want to write

ProgressFunction.BindUFunction(this, NAMEOF(&MyActor::HandleProgress));

instead of

ProgressFunction.BindUFunction(this, "HandleProgress");

where BindUFunction's second parameter can only accept TCHAR*.

Question

How to define NAMEOF macro to convert &Whatever::FunctionName to "FunctionName"?

Why do you want to write `NAMEOF(&MyActor::HandleProgress)` instead of `NAMEOF(HandleProgress)`? You like making work for yourself? Or do you have a use in mind that does not appear in the question? — JaMiT, Oct 23 '22 at 22:20

KamilCuk · Accepted Answer · 2022-10-23T22:28:17.477

4

You could stringify the argument and find the last : in it.

#include <cstring>
#include <iostream>
#define NAMEOF(x)   (strrchr(#x, ':') ? strrchr(#x, ':') + 1 : #x)
int main() {
    std::cout << NAMEOF(&MyActor::HandleProgress);
}

This is very similar to https://stackoverflow.com/a/38237385/9072753 .

edited Oct 23 '22 at 22:28

answered Oct 23 '22 at 22:25

KamilCuk

120,984
8
59
111

Oh right, that'll do it (how _dare_ you use C functions!) – Paul Sanders Oct 23 '22 at 22:26
1

@TheRealMasochist MSVC has a wide string equivalent (`_tcsrchr` handles both) if you need it. And declare that parameter `const`! – Paul Sanders Oct 23 '22 at 22:31
OK. It works as well for `NAMEOF(HandleProgress)`. – The Real Masochist Oct 23 '22 at 22:32
Yep, that's what that ternary operator is in there for – Paul Sanders Oct 23 '22 at 22:47

How to write a macro to convert member function to a string of its name?

Question

1 Answers1