C for-loop doesn't work, it just skips. Why?

Question

Made a C for-loop, and it doesn't get into it. It just skips it entirely, and I don't know why

int main(void) {
  int N = 5;
  int input;
  scanf("%d", &input);

  int c;
  for(c=0; c==N; c++) {
    srand(time(0));
    int random = rand() % 99;
    printf("Loteria: %d\n", random);
    
    if (input == random) {
      printf("\nAcertou!\n");
    }
  }
  return 0;
}

[srand() — why call it only once?](https://stackoverflow.com/questions/7343833/srand-why-call-it-only-once) — Lundin, Nov 10 '22 at 12:09

score 1 · Accepted Answer · answered Nov 10 '22 at 12:39

It appears you misunderstood the for loop termination condition.

The condition part in for ( ; condition ; ) does not specify when to stop, but how long to continue if true. A tiny change of your condition should work:

for (c = 0; c < N; c++) {

This is the idiomatic code to iterate a loop exactly N times.

C for-loop doesn't work, it just skips. Why?

1 Answers1