struct node * void expected identifier or '(' before 'void'

Question

There is a function like this. I took this error expected identifier or '(' before 'void' How to solve this problem? Thank you.

struct node * void ekleSirali(struct node * r,int x){
     if(r==NULL){
        r=(struct node *)malloc(sizeof(struct node));
        r->next=NULL;
        r->x =x;     
        return r;  
     }

I don't know whether I should write struct.

On an unrelated note, in C you [don't have to (and really shouldn't) cast the result of `malloc`](https://stackoverflow.com/questions/605845/do-i-cast-the-result-of-malloc/605858). — Some programmer dude, Nov 14 '22 at 18:09
Sidenote: `r=(struct node *)malloc(sizeof(struct node));` can be simplified to `r = malloc(sizeof *r);` — Ted Lyngmo, Nov 14 '22 at 18:09
And be careful when you assign to local argument variables. If you don't actually use the pointer that `ekleSirali` returns, your code calling the function will cease to work. — Some programmer dude, Nov 14 '22 at 18:11

Vlad from Moscow · Accepted Answer · 2022-11-14T18:13:06.963

4

The type specifier void is redundant and invalid in this context. Write

struct node * ekleSirali(struct node * r,int x){

That is the function return type can be either void (if the function returns nothing) or struct node * (if the function returns a pointer of the type struct node * as shown in your code snippet).

edited Nov 14 '22 at 18:13

answered Nov 14 '22 at 18:07

Vlad from Moscow

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struct node * void expected identifier or '(' before 'void'

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