Fastest way to check if string contains only digits in C#

Question

I know a few ways of how to check if a string contains only digits:
RegEx, int.parse, tryparse, looping, etc.

Can anyone tell me what the fastest way to check is?

I need only to CHECK the value, no need to actually parse it.

By "digit" I mean specifically ASCII digits: 0 1 2 3 4 5 6 7 8 9.

This is not the same question as Identify if a string is a number, since this question is not only about how to identify, but also about what the fastest method for doing so is.

Answer 1

bool IsDigitsOnly(string str)
{
    foreach (char c in str)
    {
        if (c < '0' || c > '9')
            return false;
    }

    return true;
}

Will probably be the fastest way to do it.

Answer 2

You could do this simply using LINQ:

return str.All(char.IsDigit);

1. .All returns true for empty strings and throws an exception for null strings.
2. char.IsDigit is true for all Unicode digit characters.

Answer 3

Here's some benchmarks based on 1000000 parses of the same string:

Updated for release stats:

IsDigitsOnly: 384588
TryParse:     639583
Regex:        1329571

Here's the code, looks like IsDigitsOnly is faster:

class Program
{
    private static Regex regex = new Regex("^[0-9]+$", RegexOptions.Compiled);

    static void Main(string[] args)
    {
        Stopwatch watch = new Stopwatch();
        string test = int.MaxValue.ToString();
        int value;

        watch.Start();
        for(int i=0; i< 1000000; i++)
        {
            int.TryParse(test, out value);
        }
        watch.Stop();
        Console.WriteLine("TryParse: "+watch.ElapsedTicks);

        watch.Reset();
        watch.Start();
        for (int i = 0; i < 1000000; i++)
        {
            IsDigitsOnly(test);
        }
        watch.Stop();
        Console.WriteLine("IsDigitsOnly: " + watch.ElapsedTicks);

        watch.Reset();
        watch.Start();
        for (int i = 0; i < 1000000; i++)
        {
            regex.IsMatch(test);
        }
        watch.Stop();
        Console.WriteLine("Regex: " + watch.ElapsedTicks);

        Console.ReadLine();
    }

    static bool IsDigitsOnly(string str)
    {
        foreach (char c in str)
        {
            if (c < '0' || c > '9')
                return false;
        }

        return true;
    }
}

Of course it's worth noting that TryParse does allow leading/trailing whitespace as well as culture specific symbols. It's also limited on length of string.

Answer 4

The char already has an IsDigit(char c) which does this:

 public static bool IsDigit(char c)
    {
      if (!char.IsLatin1(c))
        return CharUnicodeInfo.GetUnicodeCategory(c) == UnicodeCategory.DecimalDigitNumber;
      if ((int) c >= 48)
        return (int) c <= 57;
      else
        return false;
    }

You can simply do this:

var theString = "839278";
bool digitsOnly = theString.All(char.IsDigit);

Answer 5

Can be about 20% faster by using just one comparison per char and for instead of foreach:

bool isDigits(string s) 
{ 
    if (s == null || s == "") return false; 

    for (int i = 0; i < s.Length; i++) 
        if ((s[i] ^ '0') > 9) 
            return false; 

    return true; 
}

---

Code used for testing (always profile because the results depend on hardware, versions, order, etc.):

static bool isDigitsFr(string s) { if (s == null || s == "") return false; for (int i = 0; i < s.Length; i++) if (s[i] < '0' || s[i] > '9') return false; return true; }
static bool isDigitsFu(string s) { if (s == null || s == "") return false; for (int i = 0; i < s.Length; i++) if ((uint)(s[i] - '0') > 9) return false; return true; }
static bool isDigitsFx(string s) { if (s == null || s == "") return false; for (int i = 0; i < s.Length; i++) if ((s[i] ^ '0') > 9) return false; return true; }
static bool isDigitsEr(string s) { if (s == null || s == "") return false; foreach (char c in s) if (c < '0' || c > '9') return false; return true; }
static bool isDigitsEu(string s) { if (s == null || s == "") return false; foreach (char c in s) if ((uint)(c - '0') > 9) return false; return true; }
static bool isDigitsEx(string s) { if (s == null || s == "") return false; foreach (char c in s) if ((c ^ '0') > 9) return false; return true; }
static void test()
{
    var w = new Stopwatch(); bool b; var s = int.MaxValue + ""; int r = 12345678*2; var ss = new SortedSet<string>(); //s = string.Concat(Enumerable.Range(0, 127).Select(i => ((char)i ^ '0') < 10 ? 1 : 0));
    w.Restart(); for (int i = 0; i < r; i++) b = s.All(char.IsDigit); w.Stop(); ss.Add(w.Elapsed + ".All .IsDigit"); 
    w.Restart(); for (int i = 0; i < r; i++) b = s.All(c => c >= '0' && c <= '9'); w.Stop(); ss.Add(w.Elapsed + ".All <>"); 
    w.Restart(); for (int i = 0; i < r; i++) b = s.All(c => (c ^ '0') < 10); w.Stop(); ss.Add(w.Elapsed + " .All ^"); 
    w.Restart(); for (int i = 0; i < r; i++) b = isDigitsFr(s); w.Stop(); ss.Add(w.Elapsed + " for     <>");
    w.Restart(); for (int i = 0; i < r; i++) b = isDigitsFu(s); w.Stop(); ss.Add(w.Elapsed + " for     -");
    w.Restart(); for (int i = 0; i < r; i++) b = isDigitsFx(s); w.Stop(); ss.Add(w.Elapsed + " for     ^");
    w.Restart(); for (int i = 0; i < r; i++) b = isDigitsEr(s); w.Stop(); ss.Add(w.Elapsed + " foreach <>");
    w.Restart(); for (int i = 0; i < r; i++) b = isDigitsEu(s); w.Stop(); ss.Add(w.Elapsed + " foreach -");
    w.Restart(); for (int i = 0; i < r; i++) b = isDigitsEx(s); w.Stop(); ss.Add(w.Elapsed + " foreach ^");
    MessageBox.Show(string.Join("\n", ss)); return;
}

Results on Intel i5-3470 @ 3.2GHz, VS 2015 .NET 4.6.1 Release mode and optimizations enabled:

time    method          ratio
0.7776  for     ^       1.0000 
0.7984  foreach -       1.0268 
0.8066  foreach ^       1.0372 
0.8940  for     -       1.1497 
0.8976  for     <>      1.1543 
0.9456  foreach <>      1.2160 
4.4559  .All <>         5.7303 
4.7791  .All ^          6.1458 
4.8539  .All. IsDigit   6.2421 

---

For anyone tempted to use the shorter methods, note that

• .All results in true for empty strings and exception for null strings
• char.IsDigit is true for all Unicode characters in the Nd category
• int.TryParse also allows white space and sign characters

Answer 6

If you are concerned about performance, use neither int.TryParse nor Regex - write your own (simple) function (DigitsOnly or DigitsOnly2 below, but not DigitsOnly3 - LINQ seems to incur a significant overhead).

Also, be aware that int.TryParse will fail if the string is too long to "fit" into int.

This simple benchmark...

class Program {

    static bool DigitsOnly(string s) {
        int len = s.Length;
        for (int i = 0; i < len; ++i) {
            char c = s[i];
            if (c < '0' || c > '9')
                return false;
        }
        return true;
    }

    static bool DigitsOnly2(string s) {
        foreach (char c in s) {
            if (c < '0' || c > '9')
                return false;
        }
        return true;
    }

    static bool DigitsOnly3(string s) {
        return s.All(c => c >= '0' && c <= '9');
    }

    static void Main(string[] args) {

        const string s1 = "916734184";
        const string s2 = "916734a84";

        const int iterations = 1000000;
        var sw = new Stopwatch();

        sw.Restart();
        for (int i = 0 ; i < iterations; ++i) {
            bool success = DigitsOnly(s1);
            bool failure = DigitsOnly(s2);
        }
        sw.Stop();
        Console.WriteLine(string.Format("DigitsOnly: {0}", sw.Elapsed));

        sw.Restart();
        for (int i = 0; i < iterations; ++i) {
            bool success = DigitsOnly2(s1);
            bool failure = DigitsOnly2(s2);
        }
        sw.Stop();
        Console.WriteLine(string.Format("DigitsOnly2: {0}", sw.Elapsed));

        sw.Restart();
        for (int i = 0; i < iterations; ++i) {
            bool success = DigitsOnly3(s1);
            bool failure = DigitsOnly3(s2);
        }
        sw.Stop();
        Console.WriteLine(string.Format("DigitsOnly3: {0}", sw.Elapsed));

        sw.Restart();
        for (int i = 0; i < iterations; ++i) {
            int dummy;
            bool success = int.TryParse(s1, out dummy);
            bool failure = int.TryParse(s2, out dummy);
        }
        sw.Stop();
        Console.WriteLine(string.Format("int.TryParse: {0}", sw.Elapsed));

        sw.Restart();
        var regex = new Regex("^[0-9]+$", RegexOptions.Compiled);
        for (int i = 0; i < iterations; ++i) {
            bool success = regex.IsMatch(s1);
            bool failure = regex.IsMatch(s2);
        }
        sw.Stop();
        Console.WriteLine(string.Format("Regex.IsMatch: {0}", sw.Elapsed));

    }

}

...produces the following result...

DigitsOnly: 00:00:00.0346094
DigitsOnly2: 00:00:00.0365220
DigitsOnly3: 00:00:00.2669425
int.TryParse: 00:00:00.3405548
Regex.IsMatch: 00:00:00.7017648

Answer 7

Function with empty validation:

public static bool IsDigitsOnly(string str)
  {             
        return !string.IsNullOrEmpty(str) && str.All(char.IsDigit);
  }

Answer 8

I like Linq and to make it exit on first mismatch you can do this

string str = '0129834X33';
bool isAllDigits = !str.Any( ch=> ch < '0' || ch > '9' );

Answer 9

if it is a single string :

if (str.All(Char.IsDigit))
{
  // string contains only digits
}

if it is a list of strings :

if (lstStr.All(s => s.All(Char.IsDigit)))
{
  // List of strings contains only digits
}

Answer 10

You can do this in a one line LINQ statement. OK, I realise this is not necessarily the fastest, so doesn't technically answer the question, but it's probably the easiest to write:

str.All(c => c >= '0' && c <= '9')

Answer 11

Probably the fastest way is:

myString.All(c => char.IsDigit(c))

Note: it will return True in case your string is empty which is incorrect (if you not considering empty as valid number/digit )

Answer 12

This should work:

Regex.IsMatch("124", "^[0-9]+$", RegexOptions.Compiled)

int.Parse or int.TryParse won't always work, because the string might contain more digits that an int can hold.

If you are going to do this check more than once it is useful to use a compiled regex - it takes more time the first time, but is much faster after that.

Answer 13

This might be coming super late!, but I'm sure it will help someone, as it helped me.

        private static bool IsDigitsOnly(string str)
        {
            return str.All(c => c >= '0' && c <= '9');
        }

Answer 14

You can try using Regular Expressions by testing the input string to have only digits (0-9) by using the .IsMatch(string input, string pattern) method in C#.

using System;
using System.Text.RegularExpression;

public namespace MyNS
{
    public class MyClass
    {
        public void static Main(string[] args)
        {
             string input = Console.ReadLine();
             bool containsNumber = ContainsOnlyDigits(input);
        }

        private bool ContainOnlyDigits (string input)
        {
            bool containsNumbers = true;
            if (!Regex.IsMatch(input, @"/d"))
            {
                containsNumbers = false;
            }
            return containsNumbers;
        }
    }
}

Regards

Answer 15

this will work perfectly, there is many other ways but this would work

bool IsDigitsOnly(string str)
    {
        if (str.Length > 0)//if contains characters
        {
            foreach (char c in str)//assign character to c
            {
                if (c < '0' || c > '9')//check if its outside digit range
                    return false;
            }
        }else//empty string
        {
            return false;//empty string 
        }

        return true;//only digits
    }

Answer 16

Another approach!

string str = "12345";
bool containsOnlyDigits = true;
try { if(Convert.ToInt32(str) < 0){ containsOnlyDigits = false; } }
catch { containsOnlyDigits = false; }

Here, if the statement Convert.ToInt32(str) fails, then string does not contain digits only. Another possibility is that if the string has "-12345" which gets converted to -12345 successfully, then there is a check for verifying that the number converted is not less than zero.

Answer 17

I did small changes @TheCodeKing's answer.

It seems that ;

for int type fastest way is TryParse

for long type fastest way is Regex.

My results below (ticks)

For int:

TryParse Max: 355788
IsDigitsOnly Max: 787013
Regex Max: 1297691

TryParse Avg: 186007
IsDigitsOnly Avg: 430963
Regex Avg: 464657,79

TryParse Min: 162742
IsDigitsOnly Min: 335646
Regex Min: 452121


For float :

TryParse Max : 3151995
IsDigitsOnly Max: 1392740
Regex Max : 1283451

TryParse Avg: 1391636
IsDigitsOnly Avg: 824029
Regex Avg: 501176

TryParse Min: 1187410
IsDigitsOnly Min: 706646
Regex Min: 476204

Code for long:

using System.Diagnostics;
using System.Text.RegularExpressions;

class Program
{
    private static Regex regex = new Regex("^[0-9]+$", RegexOptions.Compiled);

    static void Main(string[] args)
    {
        Stopwatch watch = new Stopwatch();
        watch.Start();
        watch.Stop();
        watch.Reset();
        List<TimeSpan> tryparse = new List<TimeSpan>();
        List<TimeSpan> isdigitsonly = new List<TimeSpan>();
        List<TimeSpan> regexss = new List<TimeSpan>();

        for (int say = 0; say < 1000; say++)
        { 
            float value;

            string test = Random.Shared.NextInt64(1000,long.MaxValue).ToString();
            watch.Start();
            for (int i = 0; i < 1000000; i++)
            {
                float.TryParse(test, out value);
            }
            watch.Stop();
            //Console.WriteLine("TryParse: " + watch.Elapsed);
            tryparse.Add(watch.Elapsed);

            watch.Reset();
            watch.Start();
            for (int i = 0; i < 1000000; i++)
            {
                IsDigitsOnly(test);
            }
            watch.Stop();
            //Console.WriteLine("IsDigitsOnly: " + watch.Elapsed);
            isdigitsonly.Add(watch.Elapsed);
            watch.Reset();
            watch.Start();
            for (int i = 0; i < 1000000; i++)
            {
                regex.IsMatch(test);
            }
            watch.Stop();
            regexss.Add(watch.Elapsed);
            watch.Reset();
            //   Console.WriteLine("Regex: " + watch.Elapsed);
     
            Console.Write("---------------------% " + (Convert.ToDecimal( say)/ 999 * 100).ToString("N2") + "---------------------------");
            Console.CursorLeft = 0;
        }
        Console.WriteLine();
        Console.WriteLine($"TryParse: {tryparse.Max(t => t.Ticks)}");
        Console.WriteLine($"IsDigitsOnly: {isdigitsonly.Max(t => t.Ticks)}");
        Console.WriteLine($"Regex: {regexss.Max(t => t.Ticks)}");
        Console.WriteLine();

        Console.WriteLine($"TryParse Avg: {tryparse.Average(t => t.Ticks)}");
        Console.WriteLine($"IsDigitsOnly Avg: {isdigitsonly.Average(t => t.Ticks)}");
        Console.WriteLine($"Regex Avg: {regexss.Average(t => t.Ticks)}");
        Console.WriteLine();
        Console.WriteLine($"TryParse Min: {tryparse.Min(t => t.Ticks)}");
        Console.WriteLine($"IsDigitsOnly Min: {isdigitsonly.Min(t => t.Ticks)}");
        Console.WriteLine($"Regex Min: {regexss.Min(t => t.Ticks)}");
        Console.ReadLine();
    }

    static bool IsDigitsOnly(string str)
    {
        foreach (char c in str)
        {
            if (c < '0' || c > '9')
                return false;
        }

        return true;
    }
}

Answer 18

Try this code:

bool isDigitsOnly(string str)
{
   try
   {
      int number = Convert.ToInt32(str);
      return true;
   }
   catch (Exception)
   {
      return false;
   }
}

Answer 19

What about char.IsDigit(myChar)?

Answer 20

Very Clever and easy way to detect your string is contains only digits or not is this way:

string s = "12fg";

if(s.All(char.IsDigit))
{
   return true; // contains only digits
}
else
{
   return false; // contains not only digits
}

Answer 21

public bool CheckforDigits(string x)
{    
    int tr;  
    return x.All(r=> int.TryParse(r.ToString(), out tr));
}