a = [1,2,3,4,5]
b = a
a.remove(a[0])
print(b)
The values of a have been stored into b before a.remove was called. I don't get how this works.
a = [1,2,3,4,5]
b = a
a.remove(a[0])
print(b)
The values of a have been stored into b before a.remove was called. I don't get how this works.
because the b list is just a reference to a list and not a copy by value. if you want to have a copy of a list, try this:
a = [1, 2, 3, 4, 5]
b = a[:]
a.remove(a[0])
print(b)