How to input a vector of arguments in a function in python?

Asked Dec 19 '22 at 19:44

Active Dec 19 '22 at 19:44

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I have a function, which takes a variable number of inputs. For example, the functions may look like fn(a0,a1,...). Now, I have a vector A=[a0,a1,...], and I want to call fn, but I'm not sure how to dynamically set the number of inputs (if handling outside of the function). I do not want to handle this inside the function.

How can I do this?

asked Dec 19 '22 at 19:44

Ralff

can u share some code – Gunesh Shanbhag Dec 19 '22 at 19:45
1

You use argument spreading: `fn(*A)` – Barmar Dec 19 '22 at 19:46
Does [this](https://stackoverflow.com/questions/45346116/how-are-pythons-unpacking-operators-and-used) answer your question? In particular, I _think_ you're looking for `fn(*A)` unless I'm missing something. – BrokenBenchmark Dec 19 '22 at 19:46
And the function should be defined `def fn(*a):` – Barmar Dec 19 '22 at 19:46
The `*` operator was what I was looking for. Thanks! I thought the `*` operator only worked on the inside of the function not the outside as well – Ralff Dec 19 '22 at 20:09

How to input a vector of arguments in a function in python?

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