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I have 4 SwiftUI View:

  • The FirstView opens the SecondView using a sheet:

          .sheet(isPresented: $showSheet) {
          SecondView()
      }

  • The SecondView opens the ThirdView using a sheet too:

      .sheet(isPresented: $showSheet) {
          ThirdView()
  }

My expectations: I want ThirdView opens FourthView using NavigationLink (on full screen with Back button in the left corner):

            NavigationLink(destination: FourthView()) {
                Text("Open FourthView")
            }

but I'm having trouble with the view hierarchy. If I want to use NavigationLink, somewhere I have to define NavigationView. If I define NavigationView in the SecondView like this:

        .sheet(isPresented: $showSheet) {
            NavigationView {
                ThirdView()
            }
        }

, I have sheet view with Back button, but I want a full screen view with Back button.

Could you help me with this views hierarchy, where should I put NavigationView?

Darya
  • 11
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    So, basically what you want is that **simultaneously**: 1) Third view dismisses itself *AND* 2) First view navigates to Fourth view. You could use `NavigationStack` with a path, available only since iOS 16.0. Otherwise, use some bindings with `if` clauses in the view. – HunterLion Dec 20 '22 at 14:25

0 Answers0