array_pop() removes it from the array.
end() changes the internal pointer.
Is the only way really some cludge like:
$my_array[array_pop(array_keys($my_array))];
?
array_pop() removes it from the array.
end() changes the internal pointer.
Is the only way really some cludge like:
$my_array[array_pop(array_keys($my_array))];
?
This works:
list($end) = array_slice($array, -1);
array_slice($array, -1) returns an array with just the last element and list() assigns the first element of slice's result to $end.
@Alin Purcaru suggested this one in comments:
$end = current(array_slice($array, -1));
Since PHP 5.4, this works too:
array_slice($array, -1)[0]
 
    
    Erm... what about reset()ting after you use end()?
$lastItem = end($myArr);
reset($myArr);
 
    
    Unfortunately
list($end) = array_slice($array, -1);
doesn't work with associative arrays. So I use
function pop_array_nondestructive( $array )
    {
    return end($array);
    }
 
    
    <?php
/**
 * Return last element from array without removing that element from array.
 * https://github.com/jdbevan/PHP-Scripts/
 * 
 * @param array $array The array to get the last element from
 * @return mixed False if $array is not an array or an empty array, else the key of the last element of the array.
 */ 
function array_peek($array) {
    if (!is_array($array)) return false;
    if (count($array)<1) return false;
    $last_key = array_pop(array_keys($array));
    return $array[$last_key];
}
?>
 
    
    $last_key = array_key_last($my_array); //Get the last key of the given array without affecting the internal array pointer.
echo $my_array[$last_key];
 
    
     
    
    end($my_array);
I see nothing bad in changing internal pointer. Nobody is using it these days anyway
