How to multiply each digit by a number in a list in order

Asked Jan 19 '23 at 14:33

Active Jan 19 '23 at 14:33

Viewed 21 times

I'm trying to create a program that will multiply each digit with a number in the list in order

so lets say my inputted number is 1234, then

1 will be multiplied by 4
2 will be multiplied by 8
3 will be multiplied by 5, and so on

frequentNum = input("please enter 4 digit frequent number: ")
arr = [4, 8, 5, 7]
for i in str(frequentNum):
  for j in arr:
    value = int(i) * j 
    print(value)

I tried this code but it multiplies each digit with every number in the list

I was trying to get an output of

asked Jan 19 '23 at 14:33

I_love_vegetables

1,575
5
12
26

2

`frequentNum` is already a string you don't need to call `str()` – Barmar Jan 19 '23 at 14:35
1

You should iterate over the list and digits in parallel, not with nested loops. `for i, j in zip(frequentNum, arr):` – Barmar Jan 19 '23 at 14:36
`for i, j in zip(arr, frequentNum): print(i * int(j))` – Steven Rumbalski Jan 19 '23 at 14:40

How to multiply each digit by a number in a list in order

0 Answers0