Create an xslt function for checking if a string contains non-ASCI characters

Question

i want to check via and xslt function if a string of an..17 and if a character like this fould it will be replaced with underscore _. My problem is that i dont know how to implement with the specific set of non ASCI characters. Should i create a set of the non ASCI characters and iterate through the string? Any ideas?

Please state which version of XSLT your processor supports - see: https://stackoverflow.com/a/25245033/3016153 — michael.hor257k, Mar 23 '23 at 10:25

michael.hor257k · Accepted Answer · 2023-03-23T11:19:28.903

1

In XSLT 2.0 or higher you can do:

replace($yourString, '[^\p{IsBasic_Latin}]', '_')

to replace all non-ASCII characters with an underscore.

Note that this will preserve all ASCII characters - including non-printable control codes.

edited Mar 23 '23 at 11:19

answered Mar 23 '23 at 10:57

michael.hor257k

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For an XSLT 1.0 solution, see: https://stackoverflow.com/a/38817745/3016153 – michael.hor257k Mar 23 '23 at 11:22
Hey! I m using XSLT 2.0 – RamAlx Mar 23 '23 at 12:08
Good. Then your question is answered, is it not? – michael.hor257k Mar 23 '23 at 12:11
I have a maybe stupid question hehe..what is the isBasic_Latin var? – RamAlx Mar 23 '23 at 12:12
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It's not a variable, it's a Unicode block: https://en.wikipedia.org/wiki/Basic_Latin_(Unicode_block) – michael.hor257k Mar 23 '23 at 12:14

Create an xslt function for checking if a string contains non-ASCI characters

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