String after character in URL

Question

I have URL, e.g. google.com/page1/page2/abc123 and my output should be abc123.

Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. — Community, Apr 25 '23 at 09:55
It would be simpler to understand, when posting a [example] of your Jinja-template, the given input and the desired output. — hc_dev, Apr 25 '23 at 10:09

score 0 · Answer 1 · answered Apr 25 '23 at 10:06

0

You could try to split the url address into a list and then get the last element of that list which would be what you need.

url = "google.com/page1/page2/abc123"
splitted_url = url.split("/")
last_element = splitted_url[-1]
print(last_element)

answered Apr 25 '23 at 10:06

Marcin

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score 0 · Answer 2 · answered Apr 25 '23 at 10:14

You have several options. One would be to split the URL into tokens based on '/' then take the last token in the returned list. Another option would be to find the last occurrence of '/' in the string then slice the string accordingly.

URL = 'google.com/page1/page2/abc123'

print(URL.split('/')[-1])
print(URL[URL.rfind('/')+1:])

String after character in URL

2 Answers2