Code outputs both negative and non-negative 0 to be true

Question

Here are two cases:

console.log(Math.abs(-16) % 2 === 0) //true
console.log(Math.abs(-16) % 2 === -0) //true

In the second case, isn't Math.abs() supposed to change -16 into 16, therefore making it return false because 16 % 2 !== -0? Also how can i solve it so that the second case (console.log(Math.abs(-16) % 2 === -0)) doesn't return true, instead, false

You can't do this because `-0 === 0` – mousetail May 24 '23 at 09:18 — mousetail, May 24 '23 at 09:18
console.log(0 === -0) // output -> true. – Shachar297 May 24 '23 at 09:18 — Shachar297, May 24 '23 at 09:18

score 1 · Answer 1 · answered May 24 '23 at 09:20

1

You need Object.is if you want to tell the difference between positive and negative zeroes:

console.log(Object.is(-16 % 2, +0)) // false
console.log(Object.is(-16 % 2, -0)) // true

answered May 24 '23 at 09:20

gog

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Code outputs both negative and non-negative 0 to be true

1 Answers1