How to notify when python thread finished

Question

I want to call callback function when thread finished. And it should be thread safe

I want solution to call a callback function when thread finished and it should be thread safe.

my_thread = threading.Thread(target=do_work)
my_thread.finished.connect(thread_finished)
my_thread.start()

Is [this answer](https://stackoverflow.com/a/6801633/21891079) helpful at all? Please expand on what you have tried so far. — Joshua Shew, Aug 10 '23 at 01:45

score 0 · Answer 1 · answered Aug 10 '23 at 02:56

0

You best bet is futures.

from concurrent.futures import ThreadPoolExecutor
from time import sleep

def do_work():
    sleep(2)
    return 10

def im_done(future):
    print("Result of future is", future.result())

with ThreadPoolExecutor() as executor:
    future = executor.submit(do_work)
    future.add_done_callback(im_done)

answered Aug 10 '23 at 02:56

Frank Yellin

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I want to use in pyqt. In callback function if I call qt widget it throws error. And it is not thread safe. Thanks for your answer – Manoj gowda Aug 20 '23 at 14:55

Mahalakshmi D · Accepted Answer · 2023-08-20T02:23:34.437

You can use this solution worked for me. And it is thread safe.



import time
from threading import Thread
from pyrvsignal import Signal


class MyThread(Thread):
    started = Signal()
    finished = Signal()

    def __init__(self, target, args):
        self.target = target
        self.args = args
        Thread.__init__(self)

    def run(self) -> None:
        self.started.emit()
        self.target(*self.args)
        self.finished.emit()


def do_my_work(details):
    print(f"Doing work: {details}")
    time.sleep(10)

def started_work():
    print("Started work")
    
def finished_work():
    print("Work finished")

thread = MyThread(target=do_my_work, args=("testing",))
thread.started.connect(started_work)
thread.finished.connect(finished_work)
thread.start()

Refer this - Notify threading events

How to notify when python thread finished

2 Answers2