Can someone explain to me how division in MIX (from TAOCP by Knuth) works on a byte-to-byte basis?
rA = |-| . . . .0|
rX = |+|1235|0|3|1|
The memory location 1000 contains |-|0|0|0|2|0|.
When you execute the operation
DIV 1000
the registers become
rA = |+|0|617|?|?|
rX = |-|0|0|0|?|1|
Now I understand the signs on rA and rX, but in what order are the bytes of rAX filled and which divisions are done?
If DIV 1000 leads to every bit divided by 2, then I would expect
rAX = |+|617|0|1|0|-|0|1|0|1|1|
in which rA contains the division results and rX the remainders (filled from the right side).
I'm probaly missing something here, and Knuth seems to think I should be able to figure it out myself (hence the level 10 questions about it, which I also don't get), but could someone help me out here?