How to create an instance of System.IO.Stream stream

Question

How to create an instance of System.IO.Stream stream. One of my function receives System.IO.Stream stream as parameter and write some thing to it. So how can I create a new instance of the same and pass it to the function ?

score 135 · Accepted Answer · answered Nov 04 '11 at 05:42

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System.IO.Stream stream = new System.IO.MemoryStream();

answered Nov 04 '11 at 05:42

Rauf

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Do we have to call Close or Dispose on such "empty" stream? – Pawel Cioch Oct 16 '13 at 17:17
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Short answer: Yes. For the longer answer, check out John Skeet's answer http://stackoverflow.com/a/234257/1480854 – Josh Jul 26 '15 at 21:14

score 25 · Answer 2 · edited Mar 03 '18 at 02:52

You have to create an instance of one of the subclasses. Stream is an abstract class that can't be instantiated directly.

There are a bunch of choices if you look at the bottom of the reference here:

Stream Class | Microsoft Developer Network

The most common probably being FileStream or MemoryStream. Basically, you need to decide where you wish the data backing your stream to come from, then create an instance of the appropriate subclass.

score 25 · Answer 3 · edited Aug 10 '18 at 20:18

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Stream stream = new MemoryStream();

you can use MemoryStream

Reference: MemoryStream

edited Aug 10 '18 at 20:18

Ritwick Dey

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answered Nov 04 '11 at 05:35

ojlovecd

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score 2 · Answer 4 · answered Nov 04 '11 at 05:34

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Stream is a base class, you need to create one of the specific types of streams, such as MemoryStream.

answered Nov 04 '11 at 05:34

Bradley Uffner

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How to create an instance of System.IO.Stream stream

4 Answers4