In Python, how do I split a string to a number of integers?

Question

This works !

>>> from datetime import date

>>> today=date(2011,10,11)

But how do I do this ?

>>> day =  '2011/10/11'

>>> today=date(day.split('/'))

note:

>>> day.split('/') 

['2011', '10', '11']

I have seen this link.But i need integers for the date() not a list

score 9 · Accepted Answer · answered Nov 10 '11 at 14:14

9

Use datetime.datetime.strptime(), which is designed specifically for parsing dates:

In [5]: datetime.datetime.strptime('2011/12/03', '%Y/%m/%d').date()
Out[5]: datetime.date(2011, 12, 3)

answered Nov 10 '11 at 14:14

NPE

score 3 · Answer 2 · answered Nov 10 '11 at 14:13

3

This should work:

date(*map(int, day.split('/')))

>>> map(int, day.split('/'))
[2011, 10, 11]
>>> date(*map(int, day.split('/')))
datetime.date(2011, 10, 11)

answered Nov 10 '11 at 14:13

Dogbert

apologies for posting a dup, beat me by seconds, no reloads. +1 – user237419 Nov 10 '11 at 14:16

score 2 · Answer 3 · answered Nov 10 '11 at 14:13

2

Python has a special syntax for passing a sequence as the arguments:

today=date(*day.split('/'))

But the parameters also have to be ints, so you can use:

today=date(*map(int,day.split('/')))

answered Nov 10 '11 at 14:13

Vaughn Cato

**passing a sequence as the arguments** That was what i wanted to know.Thanks.But aix has the more appropriate answer. – Jibin Nov 11 '11 at 09:47

score 2 · Answer 4 · edited Nov 10 '11 at 14:24

2

You can loop over the list you get from day.split() and convert each entry to an int.

today = date([int(x) for x in day.split('/')])

edited Nov 10 '11 at 14:24

glglgl

answered Nov 10 '11 at 14:15

ethan

score 0 · Answer 5 · answered Nov 10 '11 at 14:15

0

>>> date( *(map(int,day.split('/'))))
datetime.date(2011, 10, 11)

answered Nov 10 '11 at 14:15

user237419

5 Answers5