How can I transform a Bitmap into a Uri?

Question

I'm trying to share images with Facebook, twitter, etc using SHARE INTENT from Android.

I found code to send a image to the share intent, but this code needs the URI of the bitmap: fullSizeImageUri

This is the full code:

private void startShareMediaActivity(Bitmap image) {
    boolean isVideo=false;
    String mimeType="bmp";
    Uri fullSizeImageUri=null;
    Intent intent = new Intent();
    intent.setAction(Intent.ACTION_SEND);
    intent.setType(mimeType);
    intent.putExtra(Intent.EXTRA_STREAM, fullSizeImageUri);
    try {
        startActivity(Intent.createChooser(intent, (isVideo ? "video" : "image")));
    } catch (android.content.ActivityNotFoundException ex) { }
}

How to transform a Bitmap into a Uri?

score 92 · Answer 1 · edited Jun 24 '20 at 03:43

92

Here is the Colin's Blog who suggest the simple method to convert bitmap to Uri Click here

public Uri getImageUri(Context inContext, Bitmap inImage) {
  ByteArrayOutputStream bytes = new ByteArrayOutputStream();
  inImage.compress(Bitmap.CompressFormat.JPEG, 100, bytes);
  String path = MediaStore.Images.Media.insertImage(inContext.getContentResolver(), inImage, "Title", null);
  return Uri.parse(path);
}

edited Jun 24 '20 at 03:43

DragonFire

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answered Apr 23 '13 at 11:22

Ajay

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Note this creates an image that will stick around in the users gallery. – ocross Mar 11 '16 at 17:35
5

path can be null, if so, Uri.parse(path) will make app crash – Roni Castro Aug 05 '17 at 22:18
3

Dont forget to take WRITE_EXTERNAL_STORAGE permission. Otherwise insertImage method may return null. See : https://stackoverflow.com/a/35283353/3341089 – oguzhan Sep 27 '17 at 07:47
@Noman If you want to delete inserted image, you can look at https://stackoverflow.com/a/16511111/3341089 – oguzhan Sep 28 '17 at 08:59
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Not workking in android oreo, String path = Images.Media.insertImage(inContext.getContentResolver(), inImage, "Title", null); path will get null. – Ashutosh Srivastava Oct 30 '17 at 13:31
The background of my image became black. How to make the background transparent? – MrinmoyMk Apr 12 '20 at 12:52
1

This method is deprecated – Abraham Mathew Feb 17 '21 at 14:49
@MrinmoyMk did you figured out how to get rid of that black background? – Spandan Saxena May 01 '21 at 18:02

KK_07k11A0585 · Accepted Answer · 2011-11-29T08:35:35.507

22

String FILENAME = "image.png";
String PATH = "/mnt/sdcard/"+ FILENAME;
File f = new File(PATH);
Uri yourUri = Uri.fromFile(f);

edited Nov 29 '11 at 08:35

answered Nov 28 '11 at 13:58

KK_07k11A0585

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Parse always take as argument a String not a file. Next time read details about functions or maybe test them. – Aurelian Cotuna Nov 29 '11 at 08:25
13

can't we get Uri without saving the bitmap – Prasad Nov 19 '14 at 09:34
work in android studio 2022 bumblebee – reza rahmad Aug 13 '22 at 08:29
@rezarahmad Dear sheldon, This was answered 10 years back, – KK_07k11A0585 Jul 28 '23 at 12:39
@KK_07k11A0585 yes this still working until 2023 and more future years – reza rahmad Jul 29 '23 at 01:56

score 5 · Answer 3 · answered Aug 30 '22 at 18:57

The latest solution I found is this. Its in kotlin you can covert it in Java.

    // Get uri of images from camera function
private fun getImageUri(inContext: Context?, inImage: Bitmap): Uri {

    val tempFile = File.createTempFile("temprentpk", ".png")
    val bytes = ByteArrayOutputStream()
    inImage.compress(Bitmap.CompressFormat.PNG, 100, bytes)
    val bitmapData = bytes.toByteArray()

    val fileOutPut = FileOutputStream(tempFile)
    fileOutPut.write(bitmapData)
    fileOutPut.flush()
    fileOutPut.close()
    return Uri.fromFile(tempFile)
}

score 4 · Answer 4 · answered Mar 11 '16 at 17:52

4

The above solution uses media store and stores the image in the users main image folder making it viewable through the gallery/photo viewer. This solution will store it as a temporary file in your apps data. In this example inImage is a Bitmap and title is a string for the name of the image file.

    File tempDir= Environment.getExternalStorageDirectory();
    tempDir=new File(tempDir.getAbsolutePath()+"/.temp/");
    tempDir.mkdir();
    File tempFile = File.createTempFile(title, ".jpg", tempDir);
    ByteArrayOutputStream bytes = new ByteArrayOutputStream();
    inImage.compress(Bitmap.CompressFormat.JPEG, 100, bytes);
    byte[] bitmapData = bytes.toByteArray();

    //write the bytes in file
    FileOutputStream fos = new FileOutputStream(tempFile);
    fos.write(bitmapData);
    fos.flush();
    fos.close();
    return Uri.fromFile(tempFile);

answered Mar 11 '16 at 17:52

ocross

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How temporary is temporary? When will the file be deleted? Can I use the same file name for several images in quick succession? – Joel Broström Mar 24 '20 at 19:25
instead of tempDir=new File(tempDir.getAbsolutePath()+"/.temp/"); you can always use a directory exclusively used by your app.. and just leave the images there – DragonFire Jun 23 '20 at 05:02
@Joel Also if you are using in a loop name the file name as "file"+i and on success of your process like an api response you can clear this folder -> that will have to be done manually – DragonFire Jun 23 '20 at 05:19

score 2 · Answer 5 · edited Aug 29 '22 at 04:59

val context = LocalContext.current
val uri = context.saveImage(bitmap) // here you will receive the Uri


private fun Context.saveImage(bitmap: Bitmap): Uri? {
    var uri: Uri? = null
    try {
        val fileName = System.nanoTime().toString() + ".png"
        val values = ContentValues().apply {
            put(MediaStore.Images.Media.DISPLAY_NAME, fileName)
            put(MediaStore.Images.Media.MIME_TYPE, "image/png")
            if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.Q) {
                put(MediaStore.MediaColumns.RELATIVE_PATH, "DCIM/")
                put(MediaStore.MediaColumns.IS_PENDING, 1)
            } else {
                val directory =
                    Environment.getExternalStoragePublicDirectory(Environment.DIRECTORY_DCIM)
                val file = File(directory, fileName)
                put(MediaStore.MediaColumns.DATA, file.absolutePath)
            }
        }

        uri = contentResolver.insert(MediaStore.Images.Media.EXTERNAL_CONTENT_URI, values)
        uri?.let {
            contentResolver.openOutputStream(it).use { output ->
                bitmap.compress(Bitmap.CompressFormat.PNG, 100, output)
            }
            if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.Q) {
                values.apply {
                    clear()
                    put(MediaStore.Audio.Media.IS_PENDING, 0)
                }
                contentResolver.update(uri, values, null, null)
            }
        }
        return uri
    }catch (e: java.lang.Exception) {
        if (uri != null) {
            // Don't leave an orphan entry in the MediaStore
            contentResolver.delete(uri, null, null)
        }
        throw e
    }
}

score 1 · Answer 6 · answered Feb 17 '17 at 08:50

1

pass bitmap and compressFormat like (PNG, JPG, etc...) and image quality in percentage

public Uri getImageUri(Bitmap src, Bitmap.CompressFormat format, int quality) {
    ByteArrayOutputStream os = new ByteArrayOutputStream();
    src.compress(format, quality, os);

    String path = MediaStore.Images.Media.insertImage(getContentResolver(), src, "title", null);
    return Uri.parse(path);
}

answered Feb 17 '17 at 08:50

Pankaj Talaviya

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path can be null, so your code would crash on Uri.parse(path) – Roni Castro Aug 05 '17 at 22:17
you check path is null or not. and after you pass in Uri – Pankaj Talaviya Aug 08 '17 at 13:15
@PankajTalaviya This method is saving the image with .jpg format even we provide PNG format to compress. – Pankaj Mundra Mar 01 '19 at 09:31
@PankajMundra Increase decrease quality percentage to compress image – Pankaj Talaviya Mar 04 '19 at 11:02
So according to you what should be the appropriate percentage to save image as .png...because if it saves as jpeg the background of image is black. – Pankaj Mundra Mar 04 '19 at 11:06

score 0 · Answer 7 · answered Apr 13 '16 at 09:01

0

String picName = "pic.jpg";
        String PATH = Environment.getExternalStorageDirectory().getPath()+ picName;
        File f = new File(PATH);
        Uri yourUri = Uri.fromFile(f);

answered Apr 13 '16 at 09:01

mehrdad khosravi

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score 0 · Answer 8 · answered Nov 28 '11 at 12:36

0

Well you can't transforma a bitmap file into a uri. Read more about URI here

URI is an Uniform Resource Identifier. But you can place the bitmap in an absolute or relative URI like this

Absolute: http://android.com/yourImage.bmp
Relative: yourImage.bmp

answered Nov 28 '11 at 12:36

Aurelian Cotuna

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then how can achieve my needs? it's impossible? – NullPointerException Nov 28 '11 at 12:39
I guess you have to rethink your way to see this... check Facebook and twitter APIS to see how you can achieve that image sharing – Aurelian Cotuna Nov 28 '11 at 13:58

How can I transform a Bitmap into a Uri?

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