bash script 4 rows in one line

Question

I have file like this:

How to get result like that by awk or similar:

1 2 3 4

For a highly rated sed solution (and an additional awk solution): http://stackoverflow.com/questions/1251999/sed-how-can-i-replace-a-newline-n — Christopher, Dec 02 '11 at 22:14

score 4 · Answer 1 · answered Dec 02 '11 at 19:48

4

echo $(cat file)

if the file is short.

awk '{printf("%s ",$0)}' <file

if you want awk or similar.

answered Dec 02 '11 at 19:48

score 1 · Answer 2 · answered Dec 02 '11 at 20:44

1

paste -sd\  infile

Note that the above command contains two white space characters (an escaped and a plain one).

answered Dec 02 '11 at 20:44

Dimitre Radoulov

Great, I always forget what these commands like `paste`, `join` do :) — I usually write it as `-sd' '` in here to avoid explanations. – Michael Krelin - hacker Dec 02 '11 at 21:00

score 0 · Answer 3 · answered Dec 02 '11 at 19:49

0

awk '{printf $0" "}' your_file

answered Dec 02 '11 at 19:49

jaypal singh

Now put `%s` into `your_file` :) – Michael Krelin - hacker Dec 02 '11 at 19:51
Do I have to? I usually put `%s` and other stuff when I need formatting. I use `printf` mostly to kill the `newline`. May be there is something to it that I am not aware. – jaypal singh Dec 02 '11 at 19:55
1

I mean, if the file contains `'%s'`, then it will be interpreted as a format string and will error out. I also used `printf` to kill the newline, but differently (see my answer). – Michael Krelin - hacker Dec 02 '11 at 19:57

score 0 · Answer 4 · answered Dec 02 '11 at 20:56

0

Perl solution:

perl -l40pe1 infile

answered Dec 02 '11 at 20:56

choroba

4 Answers4